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olasank [31]
4 years ago
14

Mg(OH)2 + HCl --> MgCl2 + H2O

Chemistry
1 answer:
Rashid [163]4 years ago
6 0
I am guessing you want us to balance this equation so.
To balance, we add another molecule of HCl to the left side of the equation and another molecule of water (H20) to the right side of the equation to give: 

<span>Mg(OH)2 + 2HCl = MgCl2 + 2H20 </span>
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When pH changes from 6 to 3, how many times does acidity increase?
photoshop1234 [79]

Since a pH of 3 is three numbers higher than a pH of 6, we can find the change in acidity by taking 10 to the third power. The solution with a pH of 3 is 1000 times more acidic than the solution with a pH of 6.

8 0
3 years ago
In the laboratory you dissolve 13.9 g of potassium phosphatein a volumetric flask and add water to a total volume of 250mL.
tensa zangetsu [6.8K]

Answer:

Molarity of the solution? 0,262 M.

Concentration of the potassium cation? 0,786 M.

Concentration of the phosphate anion? 0,262 M.

Explanation:

Potassium phosphate (K₃PO₄; 212,27 g/mol) dissolves in water thus:

K₃PO₄ → 3 K⁺ + PO₄³⁻ <em>(1)</em>

Molarity is an unit of chemical concentration given in moles of solute (K₃PO₄) per liters of solution.

There are 250 mL of solution≡0,25 L

The moles of K₃PO₄ are:

13,9 g of K₃PO₄ ×\frac{1mol}{212,27 g} = 0,0655 moles of K₃PO₄

The molarity of the solution is:

\frac{0,0655 moles}{0,25L} = 0,262 M

In (1) you can see that 1 mole of K₃PO₄ produces 3 moles of potassium cation. The moles of potassium cation are:

0,0655 moles×3 = 0,1965 moles

The concentration is:

\frac{0,1965 moles}{0,25L} = 0,786 M

The moles of K₃PO₄ are the same than moles of PO₄³⁻, thus, concentration of phosphate anion is the same than concentration of K₃PO₄. 0,262 M

I hope it helps!

4 0
3 years ago
Which of the following is true about a compound and its elements?
BaLLatris [955]
 They can change properties completely 
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6 0
4 years ago
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postnew [5]
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I think this is correct. Good luck
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9A. A sample of hydrogen at 1.56 atm had it's pressure decreased to 0.73
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Answer:idk

Explanation:

Idk

8 0
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