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Vinil7 [7]
4 years ago
14

A student measures the mass of a substance as 1.7132kg and it's volume as 0.65l. What is the density substance in g/mL? Round yo

ur answer to the correct number of significant figures
Chemistry
1 answer:
Anna007 [38]4 years ago
6 0

Answer:

The substance has a density of 2.636 grams per mililiter.

Explanation:

We must remember that density (\rho), measured in grams per mililiters, is the mass of the substance (m), measured in grams, divided by its volume (V), measured in mililiters. That is:

\rho = \frac{m}{V}

In addition, a kilogram equals 1000 grams and a liter equals 1000 mililiters. If we know that m = 1713.2\,g and V = 650\,mL, then:

\rho = \frac{1713.2\,g}{650\,mL}

\rho = 2.636\,\frac{g}{mL}

The substance has a density of 2.636 grams per mililiter.

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A very old tree limb contains an amount of carbon-14 that is approximately 1/8 of the current atmospheric 14C levels.. Calculate
Tomtit [17]

A.       The radioactive decay equation is N = N0e^{-ln(2)*t/T }

where T is the half-life (5730 years), N0 is the number of atoms at time t = 0 and N is the number at time t.

Rewriting this as:

(N/N0) = e^{-ln(2)*t/T }

Since N = (1/8) N0 and substituting known values:

1/8 = e^{-ln(2)*t/5730}

Taking ln of both sides:

ln(1/8)= -ln(2)*t/5730

t = - 5730 * ln(1/8) / ln (2)

t = 17,190 years

The tree was cut down 17,190 years ago.

B.   N0 = 1,500,000 carbon-14 atoms

Since N = (1/8) N0

N = 187,500 carbon atoms left

3 0
3 years ago
N
bazaltina [42]

Answer:

electron - proton

Explanation:

fsger

5 0
3 years ago
Read 2 more answers
For a tablet containing 500. mg of vitamin C, calculate how many ml of 0.095 M NaOH is required to reach the equivalence point.
Gala2k [10]

Answer:

mL of NaOH required =29.9mL

Explanation:

Let us calculate the moles of vitamin C in the tablet:

The molar mass of Vitamin C is 176.14 g/mole

moles=\frac{mass}{molarmass}=\frac{500mg}{176.14}=\frac{0.5}{176.14}=0.0028

Thus we need same number of moles of NaOH to reach the equivalence point.

For NaOH solution:

moles=MolarityXvolume=0.095Xvolume

0.00283=0.095Xvolume

volume=0.0299L=29.9mL

7 0
4 years ago
How many 3-liter balloons could the 12-L helium tank pressurized to 160 atm fill? Keep in mind that an "exhausted" helium tank i
vaieri [72.5K]

Answer:

The 12L helium tank pressurized to 160 atm will fill <em>636 </em>3-liter balloons

Explanation:

It is possible to answer this question using Boyle's law:

P_1V_1=P_2V_2

Where P₁ is the pressure of the tank (160atm), V₁ is the volume of the tank (12L), P₂ is the pressure of the balloons (1atm, atmospheric pressure) And V₂ is the volume this gas will occupy at 1 atm, thus:

160atm×12L = 1atm×V₂

V₂ = 1920L

As the tank will never be empty, the volume of the gas able to fill balloons is the total volume minus 12L, thus the volume of helium able to fill balloons is:

1920L - 12L = 1908L

1908L will fill:

1908L×\frac{1balloon}{3L} = <em>636 balloons</em>

<em></em>

I hope it helps!

7 0
4 years ago
A chemical reaction that is expected to form 325.0 gof product only forms 123.8 g of product. What is the percent yield of this
Tasya [4]

Answer:

\boxed {\boxed {\sf A. \ 38.1 \%}}

Explanation:

Percent yield is the ratio of the amount actually produced to how much could theoretically be produced. It is found using this formula:

\% \ yield = \frac{actual \ yield}{theoretical \ yield} *100

For this reaction, the theoretical or expected yield is 325.0 grams. The actual yield is 123.8 grams.

\% \ yield = \frac{ 123.8 \ g }{325.0 \ g }*100

Divide.

\% \ yield = 0.380923077 *100

\% \ yield = 38.0923077

Round to the nearest hundredth. The 9 in the hundredth place tells us to round the 0 to a 1 .

\% \ yield \approx 38.1

The percent yield is about <u>38.1%</u>

5 0
3 years ago
Read 2 more answers
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