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Vinil7 [7]
3 years ago
14

A student measures the mass of a substance as 1.7132kg and it's volume as 0.65l. What is the density substance in g/mL? Round yo

ur answer to the correct number of significant figures
Chemistry
1 answer:
Anna007 [38]3 years ago
6 0

Answer:

The substance has a density of 2.636 grams per mililiter.

Explanation:

We must remember that density (\rho), measured in grams per mililiters, is the mass of the substance (m), measured in grams, divided by its volume (V), measured in mililiters. That is:

\rho = \frac{m}{V}

In addition, a kilogram equals 1000 grams and a liter equals 1000 mililiters. If we know that m = 1713.2\,g and V = 650\,mL, then:

\rho = \frac{1713.2\,g}{650\,mL}

\rho = 2.636\,\frac{g}{mL}

The substance has a density of 2.636 grams per mililiter.

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The law of conservation of energy has not been broken, provided energy is released from the fission process.

<h3>What is the law of conservation of energy?</h3>

The law states that the total energy of a process is conserved. That is, the total energy or mass of a system before and after undergoing processing remains the same. However, some of the mass/energy can be converted to another form.

When a material undergoes fission, the sum total of the mass of the particles formed should be equal to the mass of the starting materials, provided that all other things remain the same.

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More on the law of conservation of energy can be found here: brainly.com/question/20971995

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Vinegar is a solution of acetic acid, CH3COOH, dissolved in water. A 5.54-g sample of vinegar was neutralized by 30.10 mL of 0.1
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Answer:

3.26 % of vinegar is acetic acid

Explanation:

Step 1: Data given

Mass of the sample = 5.54 grams

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Step 2: The balanced equation

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Step 3: Calculate moles NaOH

Moles NaOH = volume * molarity

Moles NaOH = 0.03010 L * 0.100M

Moles NaOH = 0.00301 moles NaOH

Step 4: Calculate moles CH3COOH

For 1 mol NaOH we need 1 mol CH3COOH

For 0.00301 moles NaOH we nee 0.00301 moles CH3COOH

Step 5: Calculate mass CH3COOH

Mass CH3COOH = moles CH3COOH * molar mass CH3COOH

Mass CH3COOH = 0.00301 moles * 60.05 g/mol

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Step 6: Calculate percent by weight of acetic acid

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