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Vinil7 [7]
3 years ago
14

A student measures the mass of a substance as 1.7132kg and it's volume as 0.65l. What is the density substance in g/mL? Round yo

ur answer to the correct number of significant figures
Chemistry
1 answer:
Anna007 [38]3 years ago
6 0

Answer:

The substance has a density of 2.636 grams per mililiter.

Explanation:

We must remember that density (\rho), measured in grams per mililiters, is the mass of the substance (m), measured in grams, divided by its volume (V), measured in mililiters. That is:

\rho = \frac{m}{V}

In addition, a kilogram equals 1000 grams and a liter equals 1000 mililiters. If we know that m = 1713.2\,g and V = 650\,mL, then:

\rho = \frac{1713.2\,g}{650\,mL}

\rho = 2.636\,\frac{g}{mL}

The substance has a density of 2.636 grams per mililiter.

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Explanation:

The valency of the element is the measure of the combining power of the element with the other atoms when the element forms compounds or molecules.

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Element A has 3 valence electrons and element B has 2 valence electrons. To find the ionic compound, the valency of the cations and the anions are interchanged and are written in subscripts. Thus,

A        B

3          2

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<u>Hence, 3 is the subscript for Element B.</u>

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The formula is used to calculate the yield of a reaction.
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How many grams of aluminum are required to react with 35 mL of 2.0 M hydrochloric acid, HCl?__ HCl + __ Al --&gt; __ AlCl3 + __
kiruha [24]

Answer:

0.6258 g

Explanation:

To determine the number grams of aluminum in the above reaction;

  • determine the number of moles of HCl
  • determine the mole ratio,
  • use the mole ratio to calculate the number of moles of aluminum.
  • use RFM of Aluminum to determine the grams required.

<u>Moles </u><u>of </u><u>HCl</u>

35 mL of 2.0 M HCl

2 moles of HCl is contained in 1000 mL

x moles of HCl is contained in 35 mL

x \: mol \:  =  \:  \frac{2 \:  \times  \: 35}{1000}  \\  = 0.07 \: moles \:

We have 0.07 moles of HCl.

<u>Mole </u><u>ratio</u>

  • Balanced equation

6HCl(aq) + 2Al(s) --> 2AlCl3(aq) + 3H2(g)

Hence mole ratio = 6 : 2 (HCl : Al

  • but moles of HCl is 0.07, therefore the moles of Al;

=  \frac{2}{6}  \times 0.07 \\  \:  = 0.0233333 \: moles

Therefore we have 0.0233333 moles of aluminum.

<u>Grams of </u><u>Aluminum</u>

We use the formula;

grams \:  = moles \:  \times  \: rfm

The RFM (Relative formula mass) of aluminum is 26.982g/mol.

Substitute values into the formula;

= 0.0233333 \: moles  \:  \times  \: 26.982 \:  \frac{g}{mol}  \\  = 0.625799 \: grams

The number of grams of aluminum required to react with HCl is 0.6258 g.

3 0
2 years ago
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