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Aleonysh [2.5K]
3 years ago
9

Based on the image below, what would an observer on the nighttime side of Earth observe?

Physics
2 answers:
Yakvenalex [24]3 years ago
6 0

Ace is right its full moon I just took the lab.

Lesechka [4]3 years ago
3 0
The moon is not in the Earth's shadow. Not even a tiny bit. So it's just a plain old Full Moon.
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How and why does the distance between 2 electrodes affect the rate of electrolysis? ...?
Rasek [7]
 <span>Nothing, in terms of the chemistry. 

The distance between the electrodes affects the electrical resistance very slightly. Increasing the distance increases the resistance and reduces the current slightly, which reduces slightly the amount of product. 

For most practical applications, for electrolysis done in a beaker, varying the distance between the electrodes will make little difference. 

Increasing the concentration of the electrolyte will increase the current flow because there are more charged particles to carry charge, and increase the product yield.</span>
4 0
3 years ago
What is a possible explanation for a set of facts that can be tested by further investigation called
Amanda [17]

Answer:

A hypothesis

Explanation:

A hypothesis is an explanation for those facts and can expierimented on.

5 0
3 years ago
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The law of ____ states that energy in a system can change forms but can never be created or destroyed.
irga5000 [103]
The law of (Thermodynamics)
8 0
3 years ago
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What is the impulse of a 3kg object accelerating from rest to 12m/s?
ale4655 [162]
To find the impulse you multiply the mass by the change in velocity (impulse=mass×Δvelocity). So in this case, 3 kg × 12 m/s ("12" because the object went from zero m/s to 12 m/s).

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6 0
3 years ago
A point charge Q is located a short distance from a point charge 3Q, and no other charges are present. If the electrical force o
weeeeeb [17]

Answer:

d) F

Explanation:

According to columb's law:

"The magnitude of electrostatic force between two charges is directly proportional to the product of magnitude of two charges and inversly proportional to separation between them."

If q₁ and q₂ are magnitude of two charges, d is distance between them and k is dielectric constant, then force F is given by

                                               

                                              F=\frac{kq_{1}q_{2}}{d^2}

According to this force exerted on point charge Q is same as that of 3Q, so force point 3Q charge experience is also F

7 0
3 years ago
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