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3 years ago

6

what is the relationship between the evolution of marsupials and the movement of earths tectonic plate? 8th Grade No links or fi

les Please

1 answer:

svetlana [45]3 years ago

8 0

Both require long periods of time to occur (possibly hundreds of years I think)

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Several light bulbs, each of resistance 1.5 Ω, are connected in a series across a 120 V source of emf. If the current through th

Leni [432]

<h3><u>Answer;</u></h3>

40 light bulbs

<h3><u>Explanation</u>;</h3>

The total resistance of components or bulbs in series is given as the sum of resistance of all the components.

Thus; if there are bulbs in series each with a resistance of 1.5 Ω, the the total resistance will be; 1.5nΩ

From the ohms law;

V = IR , where V is the voltage, I is the current and R is the resistor.

Thus; R = V/i

R = 120/2

= 60 Ω

But, there are n bulbs each with 1.5 Ω; thus there are;

n = 60/1.5

<u> = 40 Bulbs </u>

7 0

3 years ago

Each of two small non-conducting spheres is charged positively, the combined charge being 40 μC. When the two spheres are 50 cm

Phantasy [73]

Answer:

1.44 x 10⁻⁶ C

Explanation:

$q_{1}$ = charge on one sphere

$q_{2}$ = charge on other sphere

$q$ = Total charge on the two spheres = 40 μC

$q_{1}+ q_{2}$ = $q$

$q_{1}+ q_{2}$ = 40 x 10⁻⁶

$q_{1}$ = (40 x 10⁻⁶) - $q_{2}$ eq-1

$r$ = distance between the two spheres = 50 cm = 0.50 m

$F$ = magnitude of force between the two spheres = 2.0 N

Magnitude of force between the two spheres is given as

$F = \frac{k q_{1} q_{2}}{r^{2}}$

$2.0 = \frac{(9\times 10^{9}) ((40\times 10^{-6}) - q_{2}) q_{2}}{0.50^{2}}$

$q_{2}$ = 1.44 x 10⁻⁶ C

7 0

3 years ago

What is atherosclerosis? What is the result of atherosclerosis?

ipn [44]

Answer:

Atherosclerosis is a disease of the arteries characterized by the deposition of plaques of fatty material on the inner walls.

Explanation:

Atherosclerosis often has no symptoms until a plaque ruptures or the buildup is severe enough to block blood flow.

5 0

3 years ago

Read 2 more answers

Force F acts between two charges, q1 and q2, separated by a distance d. If q1 is increased to twice its original value and the d

vodka [1.7K]

Okay, haven't done physics in years, let's see if I remember this.

So Coulomb's Law states that $F = k \frac{Q_1Q_2}{d^2}$ so if we double the charge on $Q_1$ and double the distance to $(2d)$ we plug these into the equation to find

<span> $F_{new} = k \frac{2Q_1Q_2}{(2d)^2}=k \frac{2Q_1Q_2}{4d^2} = \frac{2}{4} \cdot k \frac{Q_1Q_2}{d^2} = \frac{1}{2} \cdot F_{old}$ </span>

So we see the new force is exactly 1/2 of the old force so your answer should be $\frac{1}{2}F$ if I can remember my physics correctly.

8 0

4 years ago

Read 2 more answers

thr koppean climate map of arizona and three different pictures of cities in arizona describe how ari pressure, temperature and

Sonbull [250]

Answer:

the tempature and the map and climate

Explanation

3 0

3 years ago