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cupoosta [38]
3 years ago
6

Which factor can increase both potential energy and kinetic energy of an object?

Physics
1 answer:
konstantin123 [22]3 years ago
5 0
I think the answer is a
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Two long, parallel wires are separated by a distance of 2.00 cm . The force per unit length that each wire exerts on the other i
RUDIKE [14]

Answer:

a) current in the second wire is 5.60A

b) opposite directions

Explanation:

a) We need to find the current of wire, the magnitude of the force per unit length between the two wires carrying current I and I¹ is given by

\frac{F}{L} = \frac{U_0I^1}{2\pi r} \\\\I^1 = \frac{F2\pi r}{LU_0I}

= (3.6 * 10^-^5)\frac{2\pi (0.02)}{4\pi * 10^-^7)(0.64)} \\= 5.60A

b) knowing that for a two parallel conductor carrying current in the same direction attracts each other, and for a two parallel conductors carrying carying current in opposite direction repels eachother.

therefore, since the two wire repel each other then the current in the second wire must flow in the opposite direction of the current in the first wire.

7 0
4 years ago
When all else remains the same, what effect would decreasing the focal have known a convex lens
harkovskaia [24]

Answer:

when all else remains the same, what effect would decreasing the focal have known a convex lens

Explanation:

It would cause the lens to produce only real images

( Hope This Will Help U Out!!)

4 0
3 years ago
A car slows down uniformly from a speed of 22 m/s to rest in 4.0 seconds. How far did it travel in that time
krek1111 [17]

Answer:

\boxed{\sf Distance \ travelled = 44 \ m}

Given:

Initial speed (u) = 22 m/s

Final speed (v) = 0 m/s (Rest)

Time taken (t) = 4 seconds

To Find:

Distance travelled by car (s)

Explanation:

From equation of motion of object moving with uniform acceleration in straight line we have:

\boxed{ \bold{s =  (\frac{v + u}{2} )t}}

By substituting value of v, u & t in the equation we get:

\sf \implies s = ( \frac{0 + 22}{2} ) \times 4 \\  \\  \sf \implies s =  \frac{22}{2}  \times 4 \\  \\  \sf \implies s = 11 \times 4 \\  \\  \sf \implies s = 44 \: m

\therefore

Distance travelled by car (s) = 44 m

4 0
4 years ago
In class we described the tidal forces that are responsible for raising and lowering thewater level near the shore of the ocean.
Sloan [31]

The newton's law of universal gravitation used to describe how a particle attracts every other particle in the universe.

The equation is given by,

F= G\frac{m_1 m_2}{r_2}

Where,

F= Gravitational force

m_1, m_2 = masses of the objects

r= is the distance between the center of their masses

G= Gravitational constant

For our problem we have defined that,

M_m = 7.24*10^{22}kg (mass of the moon)

d= 3.84*10^8 km (distance Earth-moon)

G= 6.671*10^{-11}Nm^2/kg^2

M=Mass of a person

We have then,

F_m = M\frac{6.67*10^-11*7.34*10^22}{3.84*10^8}

F_m = M*3.320*10^{-5} N

In the other hand we have the force on m-mass due to earth

F_E= MG = M*9.8N

Ratio is given by

\frac{F_m}{F_E} = {M*3.320*10^{-5}}{9.8} = 3.387*10^{-6}

B) Suppose there is a group of young people surfing in the moonlight. They are directly under the moon. At this time the moon exerts its gravitational effect of the earth that causes the tide to rise. Around 6 hours later, when the earth has moved a quarter of the moon, the force on that point decreases, so the tide drops. However, after another 6 hours, people return and experience the same process. In this case the moon is not above them, but on the other side. This is because the moon having an orbit on the earth, generates an external force, similar to the previous one, but the earth reacts in the opposite way. It is like going in a car and turning it, all people will tend to get out of it, because a centrifugal force is experienced.

7 0
4 years ago
Three out of four crashes happen at a speed of __________ miles per hour or less.
Nitella [24]
<span>The answer is 45 miles per hour or even less. Most crashes occur at a speed of 45 miles per hour or even less, and most of these accidents occur close to our homes. These crashes may also be caused by different factors, such as being drunk or sudden occurrences that are not controllable, which is why it is best to precede with caution when driving at crowded areas.</span>
5 0
3 years ago
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