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MariettaO [177]

3 years ago

6

How does adversity lead to change?

1 answer:

Umnica [9.8K]3 years ago

5 0

Answer:Adversity is a great tool of change.

Explanation:

Adversity leads to growth and change. It makes you think rightly ,manage situations and make decisions that can bring about change. Adversity can also cause positive change in attitude and behaviour towards .individuals,friends and family.

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A compound contains only carbon, hydrogen, and oxygen. combustion of 11.75 mg of the compound yields 17.61 mg co2 and 4.81 mg h2

Ymorist [56]

Number of moles is defined as the ratio of given mass in g to the molar mass.

First, convert the given mass of carbon dioxide in mg to g:

1 mg = 0.001 g

17.61 mg = 0.01761 g

Number of moles of carbon dioxide = $\frac{0.01761 g}{44.01 g/mol}$

= $0.0004001 mol$

Mass of carbon = number of moles of carbon dioxide \times molar mass of carbon

= $0.0004001 mol\times 12.011 g/mol$

= $0.004806 g$

Number of moles of water= $\frac{0.00481 g}{18 g/mol}$

= $2.672\times 10^{-4}$

Since, water contains two hydrogen atoms. Thus,

Moles of hydrogen = $2\times 2.672\times 10^{-4}$

= $5.34\times 10^{-4}$

Mass of hydrogen = $5.34\times 10^{-4}\times \times 1.008 g/mol$

= $5.34\times 10^{-4} g$

Mass of oxygen = $0.001175-(5.38\times 10^{-4}g+0.004806 g)$

= $0.006405 g$

Number of moles of oxygen = $\frac{0.006405 g}{15.999 g/mol}$

= $0.000400$

Now,

$C_{0.0004001} H_{0.000534} O_{0.000400}$

Divide the smallest number to get the whole number,

$C_{\frac{0.0004001}{0.000400}} H_{\frac{0.000534}{0.000400}} O_{\frac{0.000400}{0.000400}}$

we get,

$C_{1} H_{1.33} O_{1}$

Now, multiply all the subscript by 3 to get the whole number,

$C_{3} H_{4} O_{3}$ (empirical fomula)

Molar mass of the compound = $3\times 12.011 g/mol+4\times 1.008 g/mol+3\times 15.999 g/mol$

= $88.062 g/mol$

Divide given molar mass of the compound with the molar mass of the compound.

= $\frac{176.1 g/mol}{88.062 g/mol}$

= $1.999\simeq 2$

Thus, multiply the subscripts of empirical formula by 2 to get the molecular formula, we get:

$C_{6}H_{8}O_{6}$

Hence, empirical formula is $C_{3}H_{4}O_{3}$ and molecular formula is $C_{6}H_{8}O_{6}$

8 0

3 years ago

Hi i was wondering if you could subscribe to my youtub/e channel, you don't have to but it would mean the world to me, and stay

Inga [223]

Answer:

ok

Explanation:

8 0

2 years ago

Read 2 more answers

Calculate the grams of ethane present in a sample containing 0.8286 moles if the molar mass of ethane is 30.067 g/mol.

BlackZzzverrR [31]

N = m/M

Where,

n = number of moles

m = mass of substance

M = molar mass of substance

0.8286 = m / 30.067

Multiply both sides by 30.067

m = 24.9135162g

5 0

2 years ago

Ano ang pang uri pldssssssss pakasagot po plsss

katrin [286]

Answer:

please if you don't have a question don't question it you wasting my time

3 0

3 years ago

The science of life or living matter in all it’s forms and phenomena? What’s it’s vocab answer?

coldgirl [10]

Answer:

Biology

Explanation:

8 0

3 years ago