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2 years ago

Why does liquid move like it does when heated in the middle?

Chemistry

1 answer:

Lapatulllka [165]2 years ago

6 0

Answer:

heating makes the alcohol molecules of the liquid move faster.

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You throw a barbeque for your friends. Before you start the grill, your propane tank has a pressure of 78 psi. When you’re finis

Dvinal [7]

Answer:

b. 485 kPa

Explanation:

Gay-Lussac's law express that the pressure of a gas under constant volume is directly proportional to the absolute temperature. The equation is:

P1T2 = P2T1

P is pressure and T absolute temperature of 1, initial state and 2, final state of the gas

Where P1 = 74psi

T2 = 20°C + 273.15 = 293.15K

P2 = ?

T1 = (95°F -32) * 5/9 + 273.15 = 308.15K

Replacing:

74psi*293.15K = P2*308.15K

70.4psi

In kPa:

70.4psi * (6.895kPa / 1psi) =

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3 years ago

Which of the following is a scientific question you could ask about the game

aniked [119]

Answer:

Answer is option C

Explanation:

If you like my answer than please mark me brainliest thanks

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3 years ago

What is a gift offered to a god by killing or burning something? Plz answer I’ll give brainlist and 50 points for free

umka2103 [35]

Answer:

it is a sacrafice to god so the spirtit can go free

Explanation:

4 0

3 years ago

Read 2 more answers

PLEASE HELP!!!

umka21 [38]

Answer:

the answer is A

Explanation:

physical changes does not change the property of matter.

7 0

2 years ago

Read 2 more answers

Calculate the solubility of hydrogen in water at an atmospheric pressure of 0.380 atm (a typical value at high altitude).

Pani-rosa [81]

The question is incomplete, here is the complete question:

Calculate the solubility of hydrogen in water at an atmospheric pressure of 0.380 atm (a typical value at high altitude).

Atmospheric Gas Mole Fraction kH mol/(L*atm)

$N_2$ $7.81\times 10^{-1}$ $6.70\times 10^{-4}$

$O_2$ $2.10\times 10^{-1}$ $1.30\times 10^{-3}$

Ar $9.34\times 10^{-3}$ $1.40\times 10^{-3}$

$CO_2$ $3.33\times 10^{-4}$ $3.50\times 10^{-2}$

$CH_4$ $2.00\times 10^{-6}$ $1.40\times 10^{-3}$

$H_2$ $5.00\times 10^{-7}$ $7.80\times 10^{-4}$

Answer: The solubility of hydrogen gas in water at given atmospheric pressure is $1.48\times 10^{-10}M$

Explanation:

To calculate the partial pressure of hydrogen gas, we use the equation given by Raoult's law, which is:

$p_{\text{hydrogen gas}}=p_T\times \chi_{\text{hydrogen gas}}$

where,

$p_A$ = partial pressure of hydrogen gas = ?

$p_T$ = total pressure = 0.380 atm

$\chi_A$ = mole fraction of hydrogen gas = $5.00\times 10^{-7}$

Putting values in above equation, we get:

$p_{\text{hydrogen gas}}=0.380\times 5.00\times 10^{-7}\\\\p_{\text{hydrogen gas}}=1.9\times 10^{-7}atm$

To calculate the molar solubility, we use the equation given by Henry's law, which is:

$C_{H_2}=K_H\times p_{H_2}$

where,

$K_H$ = Henry's constant = $7.80\times 10^{-4}mol/L.atm$

$p_{H_2}$ = partial pressure of hydrogen gas = $1.9\times 10^{-7}atm$

Putting values in above equation, we get:

$C_{H_2}=7.80\times 10^{-4}mol/L.atm\times 1.9\times 10^{-7}atm\\\\C_{CO_2}=1.48\times 10^{-10}M$

Hence, the solubility of hydrogen gas in water at given atmospheric pressure is $1.48\times 10^{-10}M$

4 0

3 years ago