What reagent is used to test for starch
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Answer : The pressure of the gas is, 0.964 atm
Solution : Given,
Volume of gas = 9040 ml = 9.040 L (1 L = 1000 ml)
Moles of gas = 0.447 moles
Temperature of gas =
Using ideal gas equation,
where,
P = pressure of the gas
V = volume of the gas
T = temperature of the gas
n = number of moles of gas
R = gas constant =
Now put all the given values in this formula, we get the pressure of the gas.
By rearranging the terms, we get
Therefore, the pressure of the gas is, 0.964 atm
Answer:
Value of is 0.090.
Explanation:
Initial molarity of =
= 0.0700 M
Construct an ICE table corresponding to the combustion reaction of carbon to determine
I (M): - 0.0700 0
C (M): - -x +2x
E (M): - 0.0700-x 2x
So, , where [CO] and
represents equilibrium concentration of CO and
respectively.
Here,
⇒x = 0.030
So, = 0.0700-x = (0.0700-0.030) = 0.040
Hence,