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Greeley [361]
3 years ago
9

Ano ang pang uri pldssssssss pakasagot po plsss​

Chemistry
1 answer:
katrin [286]3 years ago
3 0

Answer:

please if you don't have a question don't question it you wasting my time

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Please comment if you are sure about your answer . Thank you
ryzh [129]
2,3,7,10,13 i did this yesterday can u mark me brainliest

3 0
3 years ago
Calculate the number of moles in a 14.5 gram sample of C4H10.
cricket20 [7]
Moles= mass divided by molar mass
Molar mass= 12.01(4) + 1.01(10)
                 = 58.14g/mol

Moles=14.5g / 58.14g/mol
         =0.249

Therefore there are approx 0.249 moles in a 14.5g sample of C4H10
6 0
2 years ago
____ can be found in many forms including in the chemicals found in food
Rzqust [24]
A. Chemical energy can be in many forms including in the chemicals found in food
4 0
2 years ago
which of the following chemical symbol is that of an element with six electrons in the outermost shell a)Ca b)Cl c)Ne d)S​
nydimaria [60]
Hey there!

Sulphur is the element which has 6 electrons in the outermost shell.

WhereasCalcium,Neon have 2 and chlorine has 7.

Hope this explanation helps you :)
Have a good day :)
5 0
1 year ago
Read 2 more answers
13. A mixture of MgCO3 and MgCO3.3H2O has a mass of 3.883 g. After heating to drive off all the water the mass is 2.927 g. What
rjkz [21]

Answer:

63.05% of MgCO3.3H2O by mass

Explanation:

<em>of MgCO3.3H2O in the mixture?</em>

The difference in masses after heating the mixture = Mass of water. With the mass of water we can find its moles and the moles and mass of MgCO3.3H2O to find the mass percent as follows:

<em>Mass water:</em>

3.883g - 2.927g = 0.956g water

<em>Moles water -18.01g/mol-</em>

0.956g water * (1mol/18.01g) = 0.05308 moles H2O.

<em>Moles MgCO3.3H2O:</em>

0.05308 moles H2O * (1mol MgCO3.3H2O / 3mol H2O) =

0.01769 moles MgCO3.3H2O

<em>Mass MgCO3.3H2O -Molar mass: 138.3597g/mol-</em>

0.01769 moles MgCO3.3H2O * (138.3597g/mol) = 2.448g MgCO3.3H2O

<em>Mass percent:</em>

2.448g MgCO3.3H2O / 3.883g Mixture * 100 =

<h3>63.05% of MgCO3.3H2O by mass</h3>
6 0
2 years ago
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