Answer:
C. The vehicle safety check indicates the ABS is functioning normally.
Explanation:
ABS, an antilock braking system, is a safe and secure slip-resistant braking system in cars and air-crafts. <u>An ABS is there to prevent wheel-locking while using brakes in vehicles</u>.
When one ignites a car, the ABS indicator will light up briefly as a part of safety check.<em> The ABS indicator light comes on for a few seconds before it turns off again. This indicates that the ABS system is functioning normally</em>. But, if the ABS indicator light remains after turning on the ignition, this indicates that there is a problem in the system.
In the given scenario, the ABS indicator is functioning properly, thus the correct answer is the third option (C).
Answer:
That's your Q seriously. Your funny. I don't have animal crossing but I do have league of legends.
Explanation:
Answer:
greater than 1
Explanation:
The mechanical advantage is the ratio Fr/Fe. So if Fr > Fe, the mechanical advantage is greater than 1.
Answer:
The system is marginally stable.
Explanation:
Transfer function, M(s) = [10(s+2)]/(s³ + 3s² + 5s)
In control the stability properties of a system can be obtained from just the characteristic equation of its closed loop transfer function.
- The condition for stability is that all the roots of the characteristic equation be negative and real.
- The condition for asymptotic stability is that all the real parts of the roots must all be negative, since there'll be complex roots.
- The condition for marginal stability is that the real part of all the complex roots are negative, the roots without real parts must have distinct imaginary parts.
- The condition for instability is for at least one of the roots to be positive. Or if there are complex roots, the real part of the roots being positive indicates instability.
The characteristic equation for this transfer function is (s³ + 3s² + 5s)
Solving this polynomial
s = 0
s = [-3 - √(11i)]/2
s = [-3 + √(11i)]/2
These roots have all their real parts to be negative, and the zero root has a distinct imaginary part, hence the system is marginally stable
Answer:
a₁= 1.98 m/s² : magnitud of the normal acceleration
a₂=0.75 m/s² : magnitud of the tangential acceleration
Explanation:
Formulas for uniformly accelerated circular motion
a₁=ω²*r : normal acceleration Formula (1)
a₂=α*r: normal acceleration Formula (2)
ωf²=ω₀²+2*α*θ Formula (3)
ω : angular velocity
α : angular acceleration
r : radius
ωf= final angular velocity
ω₀ : initial angular velocity
θ : angular position theta
r : radius
Data
r =0.4 m
ω₀= 1 rad/s
α=0.3 *θ , θ= 2π
α=0.3 *2π= 0,6π rad/s²
Magnitudes of the normal and tangential components of acceleration of a point P on the rim of the disk when theta has completed one revolution.
We calculate ωf with formula 3:
ωf²= 1² + 2*0.6π*2π =1+2.4π ²= 24.687
ωf=
=4.97 rad/s
a₁=ω²*r = 4.97²*0.4 = 1.98 m/s²
a₂=α*r = 0,6π * 0.4 = 0.75 m/s²
