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kykrilka [37]
3 years ago
6

Select all of the items that are true about a sample of water vapor at 101°C as it cools.

Chemistry
2 answers:
tia_tia [17]3 years ago
7 0
The answer would be: <span>A) Its temperature will fall continuously until it condensed into a liquid.
</span><span>
If a water vapour cools, the temperature will continuously drop till it similar to the room temperature. Since the temperature of the room is not stated, it will be hard to determine to what point will the vapour cools.
Option A sound good, the temperature will drop until it condensed into a liquid, but it could drop more after that.  Option B is a bit vague since the vapour can steadily drop below </span><span>100°C.
</span>Option C is false, the potential energy should be decreased since the condensed water would be pulled by gravitation. Option D is false because the temperature will continue to drop even if not all the vapour condenses.
Dvinal [7]3 years ago
4 0
<h3><u>Answer;</u></h3>

A) Its temperature will fall continuously until it condensed into a liquid.

<h3><u>Explanation</u>;</h3>
  • <em><u>Steam or water vapor is the gaseous state of liquid water.  When water vapor above a temperature of 100 degrees Celsius is cooled, the temperature falls continuously, and it undergoes condensation at a temperature of 100 degrees Celsius and turns into liquid water.</u></em>
  • The change of state from gaseous to liquid state occurs as a result of latent heat of vaporization that the water vapor carries.
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An object has a mass of 45.0 g and a volume of 4.0 ml. what is its density?
andreev551 [17]

Answer:

The answer is

<h2>11.25 g/mL</h2>

Explanation:

The density of a substance can be found by using the formula

Density =  \frac{mass}{volume}

From the question

mass = 45 g

volume = 4 mL

Substitute the values into the above formula and solve for the density

We have

Density =  \frac{45}{4}

We have the final answer as

<h3>11.25 g/mL</h3>

Hope this helps you

4 0
3 years ago
A sample of an ideal gas at 1.00 atm and a volume of 1.72 l was placed in a weighted balloon and dropped into the ocean. as the
kolbaska11 [484]
If we analyze the situation analytically, there are situations or states. Then, we are also given with 2 values of pressure and 1 value of volume. Lastly, temperature was set as constant. Thus, this means we use the Boyle's Law.

P₁V₁ = P₂V₂
Let's find V₂.
(1 atm)(1.72 L) = (35 atm)(V₂)
Solving for V₂,
<em>V₂ = 0.049 L</em>
7 0
3 years ago
True or false, The four units that must always be used when using the ideal gas are 44.0 liters
Bogdan [553]

Answer:

for volume only liters can be used

Explanation:

4 0
3 years ago
A 0.0200 gram piece of unknown alkaline earth metal, M, is reacted with excess 0.500 M H 2 SO 4 , and the hydrogen gas produced
Rama09 [41]

Answer:

0.981atm

Explanation:

According ot Dalton's law total pressure of a mixture of non-reactive gas is equal to sum of partial pressures of individual gases.

total pressure= 1.01at

Number of gases=2

Gases: water vapor and hydrogen

partial pressure of water vapor= 0.029atm

1.01= partial pressure of water vapor+ partial pressure of hydrogen

1.01= 0.029 + partial pressure of hydrogen

partial pressure of hydrogen = 0.981atm

6 0
3 years ago
2. Calculate the atomic mass of an element that has two isotopes, each with 50.00% abundance. One isotope has a mass of 63.00 am
melamori03 [73]

Answer:

The atomic mass of element is 65.5 amu.

Explanation:

Given data:

Abundance of X-63 = 50.000%

Atomic mass of  X-63 = 63.00 amu

Atomic mass of X-68 = 68.00 amu

Atomic mass of element = ?

Solution:

Abundance of X-68 = 100-50 = 50%

Average atomic mass = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass)  / 100

Average atomic mass  = (50×63)+(50×68) /100

Average atomic mass =  3150 + 3400 / 100

Average atomic mass  = 6550 / 100

Average atomic mass = 65.5 amu.

The atomic mass of element is 65.5 amu.

7 0
3 years ago
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