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3 years ago

Explain what happens during a solar eclipse

Chemistry

2 answers:

marusya05 [52]3 years ago

7 0

Answer:

the moon gets in the way of the sun and cast a shadow onto earth

Explanation:

erma4kov [3.2K]3 years ago

4 0

Answer:

a solar eclipse is when the moon moves between the earth and the sun, so the moon casts a shadow on the earth

Explanation:

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Theoretical yield and percentage yield of:

dem82 [27]

Answer:

Theoretical yield of potassium nitrate = 1.21 g

Theoretical yield of lead iodide = 2.77 g

Explanation:

Given data:

Mass of Lead nitrate = 2.00 g

Mass of potassium iodide = 3.00 g

Theoretical yield = ?

Percent yield = ?

Solution:

Chemical equation:

Pb(NO₃)₂ + 2KI → PbI₂ + 2KNO₃

Now we will calculate the number of moles of lead nitrate.

Number of moles = mass/ molar mass

Number of moles = 2.00 g/ 331.2 g/mol

Number of moles = 0.006 mol

Number of moles of KI:

Number of moles = mass/ molar mass

Number of moles = 3.00 g/ 166 g/mol

Number of moles = 0.02 mol

Now we will compare the moles of lead nitrate with potassium iodide with lead iodide and potassium nitrate.

Pb(NO₃)₂ : PbI₂

1 : 1

0.006 : 0.006

Pb(NO₃)₂ : KNO₃

1 : 2

0.006 : 0.006×2 =0.012

KI : PbI₂

2 : 1

0.02 : 1/2×0.02 = 0.01

KI : KNO₃

2 : 2

0.02 : 0.02

Theoretical yield of both product depend upon lead nitrate because it is limiting reactant.

Theoretical yield of potassium nitrate:

Mass = number of moles × molar mass

Mass = 0.012 mol × 101.1 g/mol

Mass = 1.21 g

Theoretical yield of lead iodide:

Mass = number of moles × molar mass

Mass = 0.006 mol × 461.01 g/mol

Mass = 2.77 g

Percentage yield can not be determine because actual yield is not given.

7 0

3 years ago

When 0.100 mol of carbon is burned in a closed vessel with8.00

antoniya [11.8K]

Answer : The mass of carbon monoxide form can be 2.8 grams.

Solution : Given,

Moles of C = 0.100 mole

Mass of $O_2$ = 8.00 g

Molar mass of $O_2$ = 32 g/mole

Molar mass of CO = 28 g/mole

First we have to calculate the moles of $O_2$ .

$\text{ Moles of }O_2=\frac{\text{ Mass of }O_2}{\text{ Molar mass of }O_2}=\frac{8g}{32g/mole}=0.25moles$

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

$2C+O_2\rightarrow 2CO$

From the balanced reaction we conclude that

As, 2 mole of $C$ react with 1 mole of $O_2$

So, 0.1 moles of $C$ react with $\frac{0.1}{2}=0.05$ moles of $O_2$

From this we conclude that, $O_2$ is an excess reagent because the given moles are greater than the required moles and $C$ is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of $CO$

From the reaction, we conclude that

As, 2 mole of $C$ react to give 2 mole of $CO$

So, 0.1 moles of $C$ react to give 0.1 moles of $CO$

Now we have to calculate the mass of $CO$

$\text{ Mass of }CO=\text{ Moles of }CO\times \text{ Molar mass of }CO$

$\text{ Mass of }CO=(0.1moles)\times (28g/mole)=2.8g$

Therefore, the mass of carbon monoxide form can be 2.8 grams.

5 0

4 years ago

"what is the mole fraction of solute in a 3.87 m aqueous solution?"

sattari [20]

The mole fraction of solute in a 3.87 m aqueous solution is 0.0697

<h3> calculation</h3>

molality = moles of the solute/Kg of the solvent

3.87 m dissolve in 1 Kg of water= 1000g

find the moles of water= mass/molar mass

that is 1000 g/ 18 g/mol= 55.56 moles

mole of solute = 3.87 moles

mole fraction is = moles of solute/moles of solvent

that is 3.87/ 55.56 = 0.0697

5 0

3 years ago

Read 3 more answers

A student has a solution with a pH of 7. The student adds HF, hydrogen floride, to the solution, hoping to increases the pH of t

Allushta [10]

Low pH = high acidity.
HF has a very low pH, so when added to a solution, it will lower the pH of the solution and therefore make it more acidic. So the answer should be B.

5 0

3 years ago

What would it take for Americans today to favor a greater reliance on nuclear power as a source of electricity

Ierofanga [76]

Answer:

yes

Explanation:

mmmm

7 0

4 years ago