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leonid [27]
3 years ago
14

How many milliliter are in 0.063 L

Chemistry
2 answers:
lidiya [134]3 years ago
7 0
63 millilitres as there are 1000ml in 1 litre
Trava [24]3 years ago
3 0

Answer:

63 mL

Explanation:

To find the amount of mililiters in an amount of liters, we must multiply by the amount of liters by 1000.

0.063 L × 1000 = 63 mL

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What is the ph of an aqueous solution with the hydronium ion concentration : [h3o+] = 3 x 10-5 m ?
BaLLatris [955]

The concentration of hydrogen can be shown as:

[H+ ] = 3 * 10-5 M

pH can be determined as:

pH = - log [H+ ]

= - log (3 * 10-5)

= 4.53

Thus the pH of solution is 4.53


8 0
3 years ago
Anna notices that different types of clothing stick together when they are dried in an electric dryer. When the clothes are pull
horrorfan [7]

Answer:

Dry more clothes at the same time so that there is less room for electric forces.

Explanation:

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2 years ago
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Here is the electron configuration for Magnesium. How many total electrons are in the 2nd energy level?
balandron [24]

Answer:

8 electrons

Explanation:

Magnesium is present on group 2.

It has 2 valence electrons.

Electronic configuration of magnesium:

Mg₁₂ = 1s² 2s² 2p⁶ 3s²

1st energy level contain 2 electrons.(1s²)

2nd energy  level contain 8 electrons. (2s² 2p⁶)

3rd energy level contain 2 electrons. (3s²)

3rs energy level of magnesium is called valence shell. It contain two valance electrons. Magnesium can easily donate its two valance electrons and get stable electronic configuration.

It react with halogens and form salt. For example,

Mg + Cl₂   →   MgCl₂

7 0
2 years ago
HELP ASAP ILL GIVE BRAINLIEST!!
Dahasolnce [82]

Of course we would experience them.

3 0
2 years ago
How many moles of S would I have if I had 11 grams? (Stoichiometry) HELP
zepelin [54]
<h3>Answer:</h3>

0.34 mol S

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

11 g S

<u>Step 2: Identify Conversions</u>

[PT] Molar Mass of S - 32.07 g/mol

<u>Step 3: Convert</u>

  1. Set up:                                \displaystyle 11 \ g \ S(\frac{1 \ mol \ S}{32.07 \ g \ S})
  2. Multiply/Divide:                  \displaystyle 0.343 \ mol \ S

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 2 sig figs.</em>

0.343 mol S ≈ 0.34 mol S

4 0
2 years ago
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