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leonid [27]
4 years ago
14

How many milliliter are in 0.063 L

Chemistry
2 answers:
lidiya [134]4 years ago
7 0
63 millilitres as there are 1000ml in 1 litre
Trava [24]4 years ago
3 0

Answer:

63 mL

Explanation:

To find the amount of mililiters in an amount of liters, we must multiply by the amount of liters by 1000.

0.063 L × 1000 = 63 mL

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si el calor fuese un fluido ¿en algun momento se agotaria después de que dos objetos se frotaran mutuamente?​
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Si el calor fuese un fluido no se agotaría, solamente cambiaría su forma o localización.

<h3>¿Qué ocurre cuando dos objetos con diferente temperatura están en contacto?</h3>

Cuando dos objetos de diferente temperatura están en contacto el calor fluye del objeto con mayor temperatura o más caliente, al objeto con menor temperatura o más frío. Esto ocurre hasta que ambos objetos alcanzan la misma temperatura.

<h3>¿Qué sucede con el calor?</h3>

El calor o energía termina se disipa hacia el entorno o la atmosfera cuando un cuerpo se enfría o hacia otro cuerpo si hay transferencia de calor, sin embargo, el calor no desaparece debido a la ley de la conservación de la energía y materia.

<h3>¿Qué sucedería si el calor fuera un fluido?</h3>

Si el calor fuera un fluido este fluido no desaparecería ni se agotaría, solamente se podría disipar a la atmósfera o ambiente.

Aprenda más sobre calor en: brainly.com/question/15890992

8 0
2 years ago
Phenolphthalein indicator was added, and the solution in the flask was titrated with 0.215M NaOH until the indicator just turned
NNADVOKAT [17]
In titration, the moles of acid equal moles of base. You were given that 22.75ml of 0.215M NaOH is used, so calculate the number of moles of that base the experiment used in total. After that because you know mol base = mol acid, whatever amount of base you use must be the total amount of acid present in the solution. You were given the volume of the acid, and you have just found the total mols of acid. Using these two information, solve for the concentration. And one more thing, even though I'm pretty sure it won't affect your answer, you should always convert things to the proper units. Since the concentration we're talking about in this problem is molarity, which has the unit mol/L, you should always have all of your numbers in these units. It just make it simpler and will not confuse you
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EXTRA POINTSSS 1. A solution at 25 degrees Celsius is 1.0 × 10–5 M H3O+. What is the concentration of OH– in this solution?
AlekseyPX

Answer:

Concentration of OH⁻:

1.0 × 10⁻⁹ M.

Explanation:

The following equilibrium goes on in aqueous solutions:

\text{H}_2\text{O}\;(l)\rightleftharpoons \text{H}^{+}\;(aq) + \text{OH}^{-}\;(aq).

The equilibrium constant for this reaction is called the self-ionization constant of water:

K_w = [\text{H}^{+}]\cdot[\text{OH}^{-}].

Note that water isn't part of this constant.

The value of K_w at 25 °C is 10^{-14}. How to memorize this value?

  • The pH of pure water at 25 °C is 7.
  • [\text{H}^{+}] = 10^{-\text{pH}} = 10^{-7}\;\text{mol}\cdot\text{dm}^{-3}
  • However, [\text{OH}^{-}] = [\text{H}^{+}]=10^{-7}\;\text{mol}\cdot\text{dm}^{-3} for pure water.
  • As a result, K_w = [\text{H}^{+}] \cdot[\text{OH}^{-}] = (10^{-7})^{2} = 10^{-14} at 25 °C.

Back to this question. [\text{H}^{+}] is given. 25 °C implies that K_w = 10^{-14}. As a result,

\displaystyle [\text{OH}^{-}] = \frac{K_w}{[\text{H}^{+}]} = \frac{10^{-14}}{1.0\times 10^{-5}} = 10^{-9} \;\text{mol}\cdot\text{dm}^{-3}.

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Answer= C) CN contains a covalent bond.

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