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oee [108]
4 years ago
12

A2.0Ω,a13Ωandan8.00Ωresistorare connected in series with a 24.0 V battery. Calculate the equivalent resistance. Answer in units

of Ω.
What is the current in the circuit? Answer in units of A.
What is the current in each resistor? Answer in units of A.
Physics
1 answer:
kykrilka [37]4 years ago
5 0

PART A)

Equivalent resistance in series is given as

R = R_1 + R_2 + R_3

now we have

R = 2 + 13 + 8

R = 23 ohm

PART B)

Here in order to find the current in the circuit we can use ohm's law

V = iR

here we have

V = 24 Volts

R = 23 ohm

24 = (i)(23 ohm)

i = 1.04 A

PART C)

Now in series circuit all branches of resistance connected to each other

so here no division of current

hence current in all resistors will be same

so we have

i_1 = i_2 = i_3 = 1.04 A

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Answer:

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4 years ago
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A mass is oscillating on the end of a spring. The distance, y, of the mass from its equilibrium point is given by the formula y=
dybincka [34]

Answer:

(a.) 4z

(b.) 4w

Explanation:

From the equation y=4zcos(8πwt), where z and w are positive constants.

Comparing this equation to the equation of a wave y = Acos(Wt), where A is the amplitude (largest distance from equilibrium) and W is the angular frequency (W=2πf)

(a.) Comparing our wave equation with the given equation, we see that A = 4z in this case (furthest distance of the mass from equilibrium)

(b.) Comparing similarly we can see from our given equation that angular frequency W =8πw we also know that W = 2πf from our wave equation, therefore 2πf = 8πw

Solving for f we have f = 8πw÷2π

f = 4w (Proves our second answer because the frequency is the number of oscillations completed per second)

3 0
3 years ago
Read the following claim.
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Explanation:

hope this helps

3 0
3 years ago
A runner starts from rest and in 3 s reaches a speed of 8 m/s. If we assume that the speed changed at a constant rate (constant
Stells [14]

Answer:

The average speed of the runner is 4 m/s.

Explanation:

Hi there!

The average speed (a.s) is calculated by dividing the traveled distance (d) over the time needed to travel that distance (t):

a.s = d / t

So, let´s find the distance traveled in those 3 s. For that, we can use the equation of position of an object moving in a straight line with constant acceleration:

x = x0 + v0 · t + 1/2 · a · t²

Where:

x = position of the object at time t.

x0 = initial position.

v0 = initial velocity.

t = time.

a = acceleration.

If we place the origin of the frame of reference at the point where the runner starts, then, x0 = 0. Since the runner starts from rest, v0 = 0. So, the equation gets reduced to this:

x = 1/2 · a · t²

We have the time (3 s), so let´s find the acceleration. For that, we can use the equation of velocity of an object moving in a straight line with constant acceleration:

v = v0 + a · t

Where "v" is the velocity at a time "t". Since v0 = 0, then:

v = a · t

At t = 3 s, v = 8 m/s

8 m/s = a · 3 s

8/3 m/s² = a

So let´s find the position of the runner at t = 3 s (In this case, the position of the runner will be equal to the traveled distance):

x = 1/2 · a · t²

x = 1/2 · 8/3 m/s² · (3 s)²

x = 12 m

Now, we can calcualte the average speed:

a.s = d/t

a.s = 12 m / 3 s

a.s = 4 m/s

The average speed of the runner is 4 m/s.

4 0
4 years ago
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