Question

A2.0Ω,a13Ωandan8.00Ωresistorare connected in series with a 24.0 V battery. Calculate the equivalent resistance. Answer in units of Ω.
What is the current in the circuit? Answer in units of A.
What is the current in each resistor? Answer in units of A.

Answer 1

PART A)

Equivalent resistance in series is given as

$R = R_1 + R_2 + R_3$

now we have

$R = 2 + 13 + 8$

$R = 23 ohm$

PART B)

Here in order to find the current in the circuit we can use ohm's law

$V = iR$

here we have

V = 24 Volts

R = 23 ohm

$24 = (i)(23 ohm)$

$i = 1.04 A$

PART C)

Now in series circuit all branches of resistance connected to each other

so here no division of current

hence current in all resistors will be same

so we have

$i_1 = i_2 = i_3 = 1.04 A$