Answer:
H_w = 2.129 m
Explanation:
given,
Width of the weir, B = 1.2 m
Depth of the upstream weir, y = 2.5 m
Discharge, Q = 0.5 m³/s
Weir coefficient, C_w = 1.84 m
Now, calculating the water head over the weir
now, level of weir on the channel
H_w = y - H
H_w = 2.5 - 0.371
H_w = 2.129 m
Height at which weir should place is equal to 2.129 m.
Answer:
The value is
Explanation:
From the question we are told that
The horizontal speed is
The horizontal distance is
Generally the time taken by the hot magma in air before landing is mathematically represented as
=>
=>
Generally the initial vertical velocity of the magma when it was lunched is
Then the final velocity of the magma when it hits the ground is mathematically represented s
Here the negative sign mean that the direction of the velocity is towards the negative y -axis
So
=>
First overtone of open organ pipe is given as
first overtone of closed organ pipe is given as
now they are in unison so we will have
so end correction of both pipes is e = 1 cm