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Dmitry [639]
3 years ago
13

What ions exist in base solutions

Physics
1 answer:
nata0808 [166]3 years ago
7 0

Answer:

In this reaction, sodium hydroxide (NaOH) disassociates into sodium (Na+) and hydroxide (OH-) ions when dissolved in water, thereby releasing OH- ions into solution. Arrhenius acids are substances which produce hydrogen ions in solution. Arrhenius bases are substances which produce hydroxide ions in solution.

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A capacitor is charged to a potential of 12.0 V and is then connected to a voltmeter having an internal resistance of 3.90 MΩ. A
iren2701 [21]

Explanation:

(a)  Formula to calculate the capacitance is as follows.

           V_{c} = V_{o} (e^(\frac{-t}{RC}))

Now, putting the given values into the above formula as follows.

          V_{c} = V_{o} (e^(\frac{-t}{RC}))

          3.5 V = 12 V (e^(\frac{-3.50 sec}{3.90 \times C}))

    e^(\frac{-3.50 sec}{3.90 \times C}) = 0.291

or,       \frac{-3.50 sec}{3.90 \times C} = ln (0.291)

      \frac{-3.50 sec}{3.90 \times C} = -1.23

              C = 0.729 F

Hence, the value of capacitance is 0.729 F.

(b)   Formula to calculate the constant of circuit is as follows.

               T = R \times C

                  = 3.1 \times 0.729

                  = 2.259 sec

Therefore, the time constant of the circuit is 2.259 sec.

5 0
4 years ago
A piston–cylinder device with a set of stops initially contains 0.6 kg of steam at 1.0 MPa and 400°C. The location of the stops
Ilya [14]

Answer:

(a) Compression work at the final state with a pressure of 1(MPa) is: 44.32(KJ), (b) Compression work at the final state with a pressure of 500(KPa): 110.37(KJ) and (c) temperaure of the final state in part b: T=151.83(°C).  

Explanation:

Remember that the substance is steam so it's water (H2O) and the initial conditions are P_{1} =1MPa, T_{1}=400^{0}C, m=0.6Kg andv_{2} =0.4v_{1} from a saturated water table and the initial conditions we can determine that the state phase is superheated (see Table 1 attached) because the T_{sat}=179.88^{0} C \leq T_{1} from the table 1 we get:v_{1} =0.30661(m^{3}/Kg). Now we have second conditions as: P_{2}=1(MPa), T_{2}=250^{0}C so from the same table we can see the state still superheated and we getv_{2}=0.23275(m^{3}/Kg), knowing that it's a isobaric process we can find the compression's work as:W_{b}=m*P(v_{2}-v_{1})=0.6*1000*(0.23275-0.30661)=-44.32(KJ) so the compressor's work is: 44.32(KJ). (b) Then the piston reaches the stop and there are two processes in this stage, so Process 1 is isobaric and:W_{1}=m*P*(v_{2}-v_{1}) =0.6*1000*(0.4*0.30661-0.30661)=-110.38(KJ) and the second process is isochoric:W_{2}=zero,nowW_{b}=W_{1}+ W_{2} =110.38+0=110.38(KJ). Finally to get the temperarure at the final state in part (b) we get:v_{2} =0.4v_{1} =0.4*0.30661=0.122644(m^{3}/Kg), P_{2}=500(KPa) from table 2 (see attached) we comparev_{f} andv_{g} at the saturated water table and find the following:v_{f}=0.001093(m^{3}/Kg), so we know that the final state phase is a satured mixture and we get the temperature at the final state as:T_{2} =T_{sat} =151.83^{0}C.

3 0
4 years ago
this stationary wave is what we call the first harmonic of the first normal mode of the system. in units of l, the length of the
Dafna1 [17]

The wavelength of the first harmonic of the standing wave is 2L.

<h3>What is a standing wave?</h3>

A standing wave is one in which the obvious points remain fixed as the vibration continues. A standing wave occurs in a wind instrument such as a trumpet, saxophone etc.

We know from  the formula of the first harmonic that the wavelength of the first harmonic of the standing wave is 2L.

Learn more about standing wave:brainly.com/question/1121886?

#SPJ11

3 0
2 years ago
Mapa conceptual y diferenciar los sistemas de unidades de medida: Internacional e inglés
Zigmanuir [339]

Answer:

dude i have no clue

Explanation:

my bad

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3 years ago
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How are surface waves similar to transverse waves?
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In longitudinal and transverse waves<span>, all the particles in the entire bulk of the medium move in a parallel and a perpendicular direction (respectively) relative to the direction of energy transport. In a </span>surface wave, it is only the particles at the surface<span> of the medium that undergo the circular motion.</span>
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3 years ago
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