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stiks02 [169]
3 years ago
13

Identify the four parts of the potential energy diagram.

Chemistry
2 answers:
Fed [463]3 years ago
4 0

I think this is how to do it. but I'm sorry if it's not exactly right

mixer [17]3 years ago
4 0

Answer : The potential energy diagram is shown below.

Explanation :

Activation energy : The energy required to initiate the reaction is known as activation energy.

Or, it is the amount of energy required to reach the transition state.

Or, It is the minimum amount of energy that is absorbed by the reactant molecules so that their energy becomes equal to the threshold energy.

Or, the difference between the reactant and the transition state.

Enthalpy of a reaction : It is the energy change which takes place when the reactants go to the products. It is represented as, \Delta H

Or, we can say that the difference between the product and the reactant.

If the heat is absorbed during the reaction then the enthalpy of reaction is positive and the reaction endothermic reaction.

If the heat is released during the reaction then the enthalpy of reaction is negative and the reaction exothermic reaction.

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Arrange the following H atom electron transitions in order of decreasing wavelength of the photon absorbed or emitted:
Katyanochek1 [597]

The decreasing order of wavelengths of the photons emitted or absorbed by the H atom is : b → c → a → d

Rydberg's formula :

                                   \frac{1}{\lambda} = R_h (\frac{1}{n_1^2}-\frac{1}{n_2^2} ),

where  λ is the wavelength of the photon emitted or absorbed from an H atom electron transition from n_1 to n_2 and R_h = 109677 is the Rydberg Constant. Here n_1 and  n_2 represents the transitions.

(a) n_1 =2 to n_2 = infinity

            \frac{1}{\lambda} = 109677\times (\frac{1}{2^2}-\frac{1}{\infty^2}  ) = 109677/4     [since 1/infinity = 0] Therefore, \lambda = 4 / 109677 = 0.00003647 m

(b) n_1=4 to  n_2 = 20

           \frac{1}{\lambda} = 109677\times (\frac{1}{4^2}-\frac{1}{20^2}  ) = 6580.62

Therefore,  \lambda = 1 / 6580.62 = 0.000152 m

(c) n_1=3 to  n_2 = 10

          \frac{1}{\lambda} = 109677\times (\frac{1}{3^2}-\frac{1}{10^2}  ) = 11089.56

Therefore,  \lambda = 1 / 11089.56 = 0.00009 m

(d)  n_1=2 to  n_2 = 1

          \frac{1}{\lambda} = 109677\times (\frac{1}{2^2}-\frac{1}{1^2}  ) = - 82257.75

Therefore,  \lambda = 1 /82257.75  = - 0.0000121 m  

[Even though there is a negative sign, the magnitude is only considered because the sign denotes that energy is emitted.]

So the decreasing order of wavelength of the photon absorbed or emitted is b → c → a → d.

Learn more about the Rydberg's formula athttps://brainly.com/question/14649374

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three moles of sodium carbonate are mixed with two moles of lead nitrate in aqueous solution, leading to formation of a solid pr
aleksandrvk [35]

There are 4 moles of spectator ions that remain in solution.

The equation of the reaction is;

Na2CO3(aq) + Pb(NO3)2(aq) -------> PbCO3(s) + 2NaNO3(aq)

We have to determine the limiting reactant. This is the reactant that yields the least amount of product. Note that the spectator ions are Na^+ and NO3^- that form NaNO3.

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1 mole of Na2CO3 yields 2 moles of NaNO3

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1 mole of Pb(NO3)2 yields 2 moles of NaNO3

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Since [NaNO3] = [Na^+] = [NO3^-], it follows that there are 4 moles of spectator ions that remain in solution.

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