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Free_Kalibri [48]
3 years ago
14

Generally the periodic trends of the d and f block is similar to the main group elements trends.

Chemistry
1 answer:
exis [7]3 years ago
7 0

Answer:

False

Explanation:

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maybe, but id rather do automotive stuff, thats my second option.

Explanation:

7 0
2 years ago
We gave an object with a density of 620 g/cm^3 and a volume of 75cm^3. What is the mass of this object?
Hitman42 [59]
d=\frac{m}{V} \ \ \ \Rightarrow \ \ m=dV\\\\
d=620\frac{g}{cm^{3}}\\
V=75cm^{3}\\\\\
m=620\frac{g}{cm^{3}}*75cm^{3}=46500g
6 0
4 years ago
Glucozo công thức phân tử
olganol [36]

Answer:I would copy and past but that’s a lot of work just read it

Explanation:

3 0
3 years ago
According to the big bang theory, which statement is accurate about how the universe came to be?
DIA [1.3K]

Answer:

The term Big Bang defines that the Universe has expanded from the ancient hot and thick primary situation at some fixed time in the past.

Big Bang theory refers to the origin of the Universe. In the beginning, universe is very heavy and small hot ball of matter. It was a point no bigger than the head of a pin when all the things squished with each other and universe is expanded with huge explosion of energy. Due to expansion, it is cooled and results in the formation of Stars and galaxies. After sometime, atoms formed like helium and hydrogen.

Thus, statement (1), (3) and (4) is correct whereas statement (2) and (5) is incorrect. the right answer is - (It expanded slowly), (Stars and galaxies formed,) (Atoms such as hydrogen and helium formed.)

Explanation:

8 0
3 years ago
Read 2 more answers
Could someone help me with this?
Varvara68 [4.7K]

Solving part-1 only

#1

KMnO_4

  • Transition metal is Manganese (Mn)

#2

Actually it's the oxidation number of Mn

Let's find how?

\\ \tt\Rrightarrow x+1+4(-2)=0

\\ \tt\Rrightarrow x+1-8=0

\\ \tt\Rrightarrow x-7=0

\\ \tt\Rrightarrow x=+7

  • x is the oxidation number

#3

  • Purple as per the color of potassium permanganate

#4

\boxed{\begin{array}{c|c|c}\boxed{\bf Tube} &\boxed{\bf Charge} &\boxed{\bf No\:of\; electrons\: loss}\\ \sf 2 &\sf +6 &\sf 6e^-\\ \sf 3& \sf +2 &\sf 2e- \\ \sf 4 &\sf 4 &\sf 4e^-\end{array}}

7 0
2 years ago
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