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My name is Ann [436]
2 years ago
6

If 0.507J of heat leads to a 0.007 degree C change in water, what mass is present?

Chemistry
1 answer:
Mamont248 [21]2 years ago
8 0

Answer:

17.3 g

Explanation:

<u>Given the following data;</u>

  • Quantity of heat, Q = 0.507 J
  • Temperature = 0.007°C
  • Specific heat capacity of water = 4.2 J/g°C

Mathematically, Heat capacity is given by the formula;

Q = MCT

Where;

  • Q represents the heat capacity or quantity of heat.
  • M represents the mass of an object.
  • C represents the specific heat capacity of water.
  • T represents the temperature.

Making "M" the subject of formula, we have;

M = \frac {Q}{CT}

Substituting the values into the formula, we have;

M = \frac {0.507}{4.2*0.007}

M = \frac {0.507}{0.0294}

<em>Mass, m = 17.3 grams</em>

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