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Yakvenalex [24]
3 years ago
6

What is true when an element is oxidized? It bonds with the hydroxide ion. It loses electrons to another element. It reacts with

oxygen gas. It takes electrons from another element.
Chemistry
1 answer:
Mama L [17]3 years ago
8 0

Answer: It loses electrons to another element.

Explanation:- Oxidation is the process in which an element loses electrons and there is an increase in the oxidation state. On losing electrons it combines with a electronegative element such as oxygen, sulphur or nitrogen etc.

Fe\rightarrow Fe^{2+}+2e^-

Reduction is the process in which an element gains electrons and there is a decrease in the oxidation state.

\frac{1}{2}O_2+2e^-\rightarrow O^{2-}

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Which set of numbers gives the correct possible values of 1 for n = 3?
Allushta [10]

Answer:

A. 0,1,2

Explanation:

took a test on it and this was the correct answer

7 0
3 years ago
Find the mass of (1) potassium which contains the same number of atoms as 5g of zinc and (2) iron which contains the same number
charle [14.2K]
Convert grams to moles
moles to moles
moles to grams

A. 2.99g
b. 20.88g

sent a picture of the work. hope you see it

5 0
4 years ago
After distilling your crude methyl benzoate, you set aside 4.83 grams of the purified ester. You then prepare the grignard reage
Ber [7]

Answer:

95.6 %

Explanation:

For this question, we will have <u>2 reactions</u>, the formation of the <u>grignard reagent</u> and the <u>formation of the alcohol</u>. The first step then is the calculation of the <u>maximum amount</u> of the grignard reagent. For this, we have to convert the grams to moles and check the smallest value. To do this we have to take into account the <u>following conversion ratios</u>:

Molar mass of Mg = 24 g/mol

Molar mass of phenylmagnesium bromide (C_6H_5Br)= 157 g/mol

Density of bromobenzene= 1.5 g/mL

Molar ratio between Mg and  C_6H_5Br= 1:1

2.3~g~Mg\frac{1~mol~Mg}{24~g~Mg}=0.096~mol~Mg

9.45~mL~\frac{1g}{1.5mL}\frac{1~mol~C_6H_5Br}{157~g}=0.0402~mol~C_6H_5Br

The smallest value is the mol of bromobenzene therefore <u>0.0402 mol</u> of phenylmagnesium bromide would be produced.

The next step is repite the same steps for the reaction of <u>formation of the alcohol</u>. Therefore we have to find the moles of methyl benzoate, so:

Molar mass of methyl benzoate: 136.14 g/mol

4.83~g~\frac{1~mol}{136.14~g}=0.35~mol

The we have to <u>divide by the coefficient</u> of each reactive in the balance reaction. So:

\frac{0.35~mol}{1}=0.35

\frac{0.0402~mol}{2}=0.0201

Therefore the <u>limiting reagent</u> would be the phenylmagnesium bromide. Now, the <u>molar ratio</u> between the phenylmagnesium bromide and triphenyl carbinol is <u>2:1</u>, so the amount of alcohol produced is 0.0201 mol triphenyl carbinol. The next step is the conversion from mol to <u>grams of triphenyl carbinol</u>:

Molar mass of triphenyl carbinol= 260.33 g/mol

0.0201~mol\frac{260.33~g}{1~mol}=5.23~g~triphenyl carbinol

Finally, we have to <u>divide</u> the obtanied solid by the calculated one:

Percentage=\frac{5}{5.23}*100=95.6\%

5 0
3 years ago
What is the [H+] of a solution with a pH of 9.40?
LiRa [457]

Answer:

a) 3.98 x 10^-10

Explanation:

Hello,

In this case, for the given pH, we can compute the concentration of hydronium by using the following formula:

pH=-log([H^+])

Hence, solving for the concentration of hydronium:

[H^+]=10^{-pH}=10^{-9.40}\\

[H^+]=3.98x10^{-10}M

Therefore, answer is a) 3.98 x 10^-10

Best regards.

4 0
3 years ago
A mixture of two compounds, A and B, was separated by extraction. After the compounds were dried, their masses were found to be:
Arlecino [84]

Answer:

The percent recovery from re crystallization for both compounds A and B is 69.745 and 81.44 % respectively.

Explanation:

Mass of compound A in a mixture  = 119 mg

Mass of compound A after re-crystallization = 83 mg

Percent recovery from re-crystallization :

\frac{\text{Mass after re-crystallization}}{\text{Mass before re-crystallization}}\times 100

Percent recovery of compound A:

\frac{83 mg}{119 mg}\times 100=69.74\%

Mass of compound B in a mixture  = 97 mg

Mass of compound B after re-crystallization = 79 mg

Percent recovery of compound B:

\frac{79 mg}{97 mg}\times 100=81.44\%

3 0
3 years ago
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