Answer:
The answer is
<h2>14.65 g/cm³</h2>
Explanation:
The density of a substance can be found by using the formula
From the question
mass of object = 14.5 g
volume = 0.99 cm³
The density of the object is
We have the final answer as
<h3>14.65 g/cm³</h3>
Hope this helps you
Answer:
hr
Explanation:
because it's short for hour
The first one is d and the second is b i think a nd. the last one is b too
According to avogadro constant, the number of units in one mole of any substance contain 6.022 x10 ^23 atoms
therefore the number of o atoms in one mole of CuSO4 = 6.022 x 10 ^ 23
I think this is what you're after:
Cs(g) → Cs^+ + e⁻ ΔHIP = 375.7 kJ mol^-1 [1]
Convert to J and divide by the Avogadro Const to give E in J per photon
E = 375700/6.022×10^23 = 6.239×10^-19 J
Plank relationship E = h×ν E in J ν = frequency (Hz s-1)
Planck constant h = 6.626×10^-34 J s
6.239×10^-19 = (6.626×10^-34)ν
ν = 9.42×10^14 s^-1 (Hz)
IP are usually given in ev Cs 3.894 eV
<span>E = 3.894×1.60×10^-19 = 6.230×10^-19 J per photon </span>