Answer:
1. C
2.C
Explanation:
1. The rod is perpendicular to every axis and forces are acting on every location. If the torque on the left side is zero, this indicates that forces with respect to their distance on the left side is zero and doesn't account for the net force at a point.
2. If the net torque about every point on every axis is zero, the rod will be rotational because each axis will yield a magnitude of zero which obeys the principle of rotation at a point.
Answer:
d = 0.076 mm
Explanation:
Given data
diffraction pattern d1 = 0.19 mm = 0.019 cm
separated s(1) = 1.8 cm
separated s(2) = 4.5 cm
to find out
d2 for an unknown
solution
we know here that spacing in between the diffraction fringe is always inversely proportional to diffraction grating so
we will apply here formula for unknown d that is
d1 (s1 / L) = d2 (s2 /L)
d2 = d1 × s(1) / s(2)
put here all thes evalue we get d2
d2 = d1 × s(1) / s(2)
d2 = 0.019 × 1.8 / 4.5
d2 = 0.0076 cm
d2 = 0.076 mm
Answer:
The work done on the hose by the time the hose reaches its relaxed length is 776.16 Joules
Explanation:
The given spring constant of the of the spring, k = 88.0 N/m
The length by which the hose is stretched, x = 4.20 m
For the hose that obeys Hooke's law, and the principle of conservation of energy, the work done by the force from the hose is equal to the potential energy given to the hose
The elastic potential energy, P.E., of a compressed spring is given as follows;
P.E. = 1/2·k·x²
∴ The potential energy given to hose, P.E. = 1/2 × 88.0 N/m × (4.20 m)²
1/2 × 88.0 N/m × (4.20 m)² = 776.16 J
The work done on the hose = The potential energy given to hose, P.E. = 776.16 J
The coordinates are- <span>RA 19° 24' 0" | Dec 59° 0.000'
It is located in the asteroid belt between mars and jupiter :)
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Answer:
1
Explanation: that is the ratio
