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3 years ago

10

The concentration of carbon monoxide in a sample of air is 8.1×10−6. There are ________ molecules of co in 1.00 l of this air at

755 torr and 23 ∘c.

1 answer:

Schach [20]3 years ago

8 0

Answer:

2.0* $10^{17}$

Explanation:

Let us calculate total moles (air + CO)

moles (n) = PV /RT

P = 755 torr/760 = 0.9934 atm

V = 1.00 L

R = gas constant

T = 23°C + 273 = 296 K

So,

total moles (n) = 0.9934 x 1.00/0.0821 x 296 = 0.041 moles

mole fraction of CO = 8.1 x $10^{-6}$

moles of CO =8.1 x $10^{-6}$ *0.041

=3.31 x $10^{-7}$ moles

number of molecule of CO =3.31 x $10^{-7}$ *(6.0233x $10^{23}$ )

= 2.0* $10^{17}$

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