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AnnyKZ [126]
2 years ago
5

Which of the following is NOT something that Earth's atmosphere protects us from? A. meteoroids B. ultraviolet light C. greenhou

se gases D. dangerous particles from space
Chemistry
2 answers:
Katarina [22]2 years ago
8 0
The answer in C. Greenhouse Gases. Greenhouse Gases is caused by the trapped heart in the atmosphere harming us which we will always have. hope this helped
QveST [7]2 years ago
3 0

Answer:

The correc answer is C. greenhouse gases.

Explanation:

The atmosphere is a layer of gases that surrounds our planet and is one of the essential elements for life on it.

The atmosphere protects us from harmful solar radiation from the Sun. The Sun, in addition to light and heat (infrared radiation), emits other radiation such as gamma rays, X-rays and ultraviolet rays that are harmful to life. These harmful radiations are absorbed by the atmosphere.

The atmosphere also protects us from the impacts of meteorites. These are from outer space are attracted by gravity and fall on the earth's surface. Upon coming into contact with the gases of the atmosphere, at high speed, the friction causes them to heat up so much that they become incandescent and end up disintegrating, avoiding reaching the ground. Only the largest (rare) can pass through the atmosphere and reach the ground.

Something similar happens that with meteorites occurs with the dangerous particles of space.

Greenhouse gases contribute, to a greater or lesser extent, to the increase of the greenhouse effect, since they are capable of absorbing the heat energy carried by long-wave radiations that are reflected by the Earth's surface.This phenomenon prevents the solar energy constantly received by the Earth from returning immediately to space and causing the temperature of the air near the ground to rise. Then there are changes in the climate such as sea level rise, changes in rainfall, disappearance of forests, extinction of organisms and problems for agriculture.

So <u><em>the correc answer is C. greenhouse gases.</em></u>

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Common brass is a copper and zinc alloy containing 37.0% zinc by mass and having a density of 8.48g/cm3. A fitting composed of c
inysia [295]
First, we calculate the mass of the sample:

mass = density x volume
mass = 8.48 x 112.5
mass = 954 grams

Now, we will calculate the mass of each component using its percentage mass, then divide it by its atomic mass to find the moles and finally multiply the number of moles by the number of particles in a mole, that is, 6.02 x 10²³.

Zinc mass = 0.37 x 954
Zinc mass = 352.98 g
Zinc moles = 352.98 / 65
Zinc moles = 5.43
Zinc atoms = 5.43 x 6.02 x 10²³
Zinc atoms = 3.27 x 10²⁴

Copper mass = 0.63 x 954
Copper mass = 601.02 g
Copper moles = 601.02 / 64
Copper moles = 9.39
Copper atoms = 9.39 x 6.02 x 10²³
Copper atoms = 5.56 x 10²⁴
3 0
3 years ago
Consider four different samples: aqueous LiBr , molten LiBr , aqueous AgBr , and molten AgBr . Current run through each sample p
Charra [1.4K]

Answer:

a) Aqueous LiBr = Hydrogen Gas

b) Aqueous AgBr = solid Ag

c) Molten LiBr = solid Li

c) Molten AgBr = Solid Ag

Explanation:

a) Aqueous LiBr

This sample produces Hydrogen gas, because the H+ (conteined in the water) has a reduction potential higher than the Li+ from the salt. Therefore the hydrogen cation will reduce instead of the lithium one and form the gas.

b) Aqueous AgBr

This sample produces Solid Ag, because the Ag+ has a reduction potential higher than the H+ from the water. Therefore the silver cation will reduce instead of the hydrogen one and form the solid.

c) Molten LiBr

In a molten binary salt like LiBr there is only one cation present in the cathod. In this case the Li+, so it will reduce and form solid Li.  

c) Molten AgBr

The same as the item above: there is only one cation present in the cathod. In this case the Ag+, so it will reduce and form solid Ag.  

6 0
3 years ago
Scenario Two:
galben [10]

Answer:

jo mom cause why not

Explanation:

7 0
3 years ago
The complete orbital notation diagram of an atom is shown.
Yuki888 [10]

Answer:

Explanation:

From the description provided by the statement of the problem, we can easily solve for the values of the angular momentum quantum number.

Let us represent the atom as J:

In atom J, we have five sub-orbitals in which there 9 electrons. From the designation used to represent sublevels, we can write the notation as below:

             J = 10 electrons = 1s² 2s² 2p⁵

The s-sublevel can only contain 2 electrons

p-sublevel can contain 6 electrons but we have just 5 electrons in there.

Now, to find the angular momentum quantum number, we need to understand what this quantum number denotes.

This quantum number is also known as azimuthal or secondary quantum number. It gives the shape of the orbitals in subshells accomodating electrons. This quantum number is designated by (l).

         l (n-1)            name of orbital               shape of orbital

             0                     s                                   spherical

             1                     p                                    dumb-bell

             2                    d                                    double dumb-bell

             3                    f                                      complex

J  = 1s² 2s² 2p⁵

where 1 and 2 coefficients are the principal quantum numbers(n).

            s and p are the shape of the orbitals

For 1s², the l vaue is 0 because the electron is in the s orbital

     2s² the l value is 0, 1 and the electron can be in the s or p orbitals

     2p⁵ the l value is 0, 1 and the electrons can be in the s or p orbitals

The quantum number gives the shape of the orbital.

8 0
3 years ago
A solution contains 35 mL of 1.50M CuSO​ . What is the molarity when the new 4​ volume is 100mL
elena-s [515]

Answer:

0.525 M CuSO

Explanation:

Molarity (M) is the units mol/L. Let's figure out how many moles of CuSO we have:

35 mL = 35/1000 L = 0.035 L

0.035 L * 1.50 mol/L = 0.0525 mol CuSO

Our new volume is 100 mL, so let's first convert this to L:

100 mL = 100/1000 L = 0.100 L

To find the new molarity, divide the number of moles (0.0525 moles) by the number of liters (0.100 L):

0.0525 mol / 0.100 L = 0.525 M CuSO

Hope this helps!

4 0
3 years ago
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