What is the number of grams of cl2 formed when 0.485 mole HCl reacts with an excess of O2

Chemistry

1 answer:

SSSSS [86.1K]3 years ago

5 0

Answer:

Mass of Cl₂ = 17.25 g

Explanation:

Given data:

Moles of hydrochloric acid = 0.485 mol

Mass of chlorine gas = ?

Chemical equation:

4HCl + O₂ → 2Cl₂ + 2H₂O

Now we will compare the moles of Cl₂ with HCl .

HCl : Cl₂

4 : 2

0.485 : 2/4× 0.485 = 0.243 mol

Oxygen is present in excess that's why mass of chlorine produce depend upon the available amount of HCl.

Mass of Cl₂ :

Mass of Cl₂ = moles × molar mass

Mass of Cl₂ =0.243 mol × 71 g/mol

Mass of Cl₂ = 17.25 g

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How many moles of hydrogen gas will be produced if 5.00 moles of zinc reactions with an excess amount of sulfuric acid

harkovskaia [24]

Answer:

Moles of Hydrogen produced is 5 moles

Explanation:

The balanced Chemical equation for reaction between zinc and sulfuric acid is :

$Zn(s) + H_{2}SO_{4}(aq) \rightarrow ZnSO_{4}(aq) + H_{2}(g)$

This equation tells that ; when 1 mole of Zn react with 1 mole of sulfuric acid, it produces 1 mole of zinc sulfate and 1 mole of hydrogen.

Since sulfuric acid is in excess so Zinc is the limiting reagent

(Limiting reagent : Substance which get consumed when the reaction completes, limiting reagent helps in predicting the amount of products formed)

Limiting reagent (Zn) will decide the amount of Hydrogen produced

$Zn(s) + H_{2}SO_{4}(aq) \rightarrow ZnSO_{4}(aq) + H_{2}(g)$

$1\ mole\ zinc\rightarrow 1\ mole\ H_{2}$