What is the number of grams of cl2 formed when 0.485 mole HCl reacts with an excess of O2
1 answer:
Answer:
Mass of Cl₂ = 17.25 g
Explanation:
Given data:
Moles of hydrochloric acid = 0.485 mol
Mass of chlorine gas = ?
Chemical equation:
4HCl + O₂ → 2Cl₂ + 2H₂O
Now we will compare the moles of Cl₂ with HCl .
HCl : Cl₂
4 : 2
0.485 : 2/4× 0.485 = 0.243 mol
Oxygen is present in excess that's why mass of chlorine produce depend upon the available amount of HCl.
Mass of Cl₂
:
Mass of Cl₂ = moles × molar mass
Mass of Cl₂ =0.243 mol × 71 g/mol
Mass of Cl₂ = 17.25 g
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