Protons and neutrons are composed of what? A electrons B.quarks C.ions D.molecules

How does glucose get into the mitochondria in autotrophs?

ozzi

The answer is by osmosis

3 0

3 years ago

Although coal is a complex mixture of substances, its elemental composition can be approximated by the formula <img src="https:/

Svetllana [295]

Answer:

The correct answer is option b.

Explanation:

$2C_{135}H_{96}O_9NS+313O_2\rightarrow 270CO_2+2NO_2+2SO_2+96H_2O$

Mass of coal burned = $1.00\times 10^6$ metric ton = 1.00\times 10^6\times 10^3 kg=10^9 kg[/tex]

1 metric ton = $10^3kg$

Molar mass of coal :

$135\times 12g/mol+96\times 1g/mol+9\times 16 g/mol+1\times 14 g/mol+1\times 32 g/mol=1906 g/mol=1.906 kg/mol$

1 g = 0.001 kg

Moles of coal ,n : $\frac{10^9 kg}{1.906 kg/mol}=5.247\times 10^8 mol$

If 2 moles of coal on combustion gives 270 moles of carbon dioxide than n moles of coal will give;

$5.247\times 10^8 mol\times \frac{270}{2}=7.083\times 10^{10} mol$ of carbon dioxide.

Molar mass of carbon dioxide gas = 44 g/mol = 0.044 kg/mol

Mass of $7.083\times 10^{10} mol$ of carbon dioxide:

$7.083\times 10^{10} mol\times 0.044 kg/mol=3.11\times 10^{11} kg$

5 0

3 years ago

Please help Explain why a molecule that has polar bonds can be a polar molecule.

Zepler [3.9K]

Answer:

Explanation:

Well, obviously a molecule with polar bonds can be polar in itself. It's like saying I am an atheltic person who can just reach the basketball rim with my head and also I can dunk.

But if the question is how can a molecule that in non-polar have polar bonds, well, its because the polar bonds' dipole cancels each other out. It's like a tight rope. If a person pulls in one direction, it intuitively, the rope would go in that direction. However, if a person pulls in the other direction with the same amount of force, the rope stays still. This is the same case. Although molecules can have different electronegativities, the pull of electrons in one direction is cancelled out by a pull in the opposite direction, making the net dipole 0.

This is common for main VSERP shaped molecules like linear, trigonal planar, tetrahedral, trigonal bipyramidal, and octahedral.

8 0

3 years ago

An atom of helium has a radius of 31. pm and the average orbital speed of the electrons in it is about 4.4x 10 m/s Calculate the

otez555 [7]

The question is incomplete, here is the complete question:

An atom of helium has a radius of 31. pm and the average orbital speed of the electrons in it is about $4.4\times 10^6m/s$ . Calculate the least possible uncertainty in a measurement of the speed of an electron in an atom of helium. Write your answer as a percentage of the average speed, and round it to 2 significant digits

Answer: The percentage of average speed is 41 %

Explanation:

We are given:

Radius of helium atom = 31 pm = $31\times 10^{-12}m$ (Conversion factor: $1m=10^{12}pm$ )

So, diameter of helium atom = $(2\times r)=(2\times 31\times 10^{-12})=64\times 10^{-12}m$

The diameter of the atom will be equal to the uncertainty in position.

The equation representing Heisenberg's uncertainty principle follows:

$\Delta x.\Delta p=\frac{h}{2\pi}$

where,

$\Delta x$ = uncertainty in position = d = $64\times 10^{-12}m$

$\Delta p$ = uncertainty in momentum = $m\Delta v$

m = mass of electron = $9.1095\times 10^{-31}kg$

h = Planck's constant = $6.627\times 10^{-34}kgm^2/s^2$

Putting values in above equation, we get:

$64\times 10^{-12}m\times 9.1095\times 10^{-31}kg\times \Delta v=\frac{6.627\times 10^{-34}kgm^2/s}{2\times 3.14}\\\\\Delta v=\frac{6.627\times 10^{-34}kgm^2/s^2}{2\times 3.14\times 64\times 10^{-12}m\times 9.1095\times 10^{-31}kg}=1.81\times 10^6m/s$

To calculate the percentage of average speed, we use the equation:

$\text{Percentage of the average speed}=\frac{\text{Uncertainty in velocity}}{\text{Average orbital speed}}\times 100$

We are given:

Average orbital speed = $4.4\times 10^6m/s$

Putting values in above equation, we get:

$\text{Percentage of the average speed}=\frac{1.81\times 10^6m/s}{4.4\times 10^6m/s}\times 100\\\\\text{Percentage of the average speed}=41.\%$

Hence, the percentage of average speed is 41 %

3 0

4 years ago

A/1 * B/C = D

Anit [1.1K]

Answer: 0.64 Moles of Propane

Explanation:

Data:

Moles of Carbon = 1.5 mol

Conversion factor = 7 mol C produces = 3 mol of Propane

Solution:

As we know,

7 moles of Carbon produces = 3 moles of Propane

Then,

1.5 moles of Carbon will produce = X moles of Propane

Solving for X,

X = (1.5 moles × 3 moles) ÷ 7 moles

X = 0.6428571 moles of Propane

Or rounded to two significant figures,

X = 0.64 Moles of Propane

Read more on Brainly.com - brainly.com/question/11464115#readmore

3 0

3 years ago