Cuantos mililitros de HC10.1M contiene 0.025 mol de HC1

lana66690 [7]

At almost the opposite point on the Earth's surface, the "P" waves reappear. The shadow zone exists because the waves are refracted as they pass through the boundary between the mantle and the core and are diverted from their original paths.

6 0

3 years ago

A sample of gas is observed to effuse through a pourous barrier in 4.98 minutes. Under the same conditions, the same number of m

kogti [31]

Answer:

The molar mass of the unknown gas is $\mathbf{ 51.865 \ g/mol}$

Explanation:

Let assume that the gas is O2 gas

O2 gas is to effuse through a porous barrier in time t₁ = 4.98 minutes.

Under the same conditions;

the same number of moles of an unknown gas requires time t₂ = 6.34 minutes to effuse through the same barrier.

From Graham's Law of Diffusion;

Graham's Law of Diffusion states that, at a constant temperature and pressure; the rate of diffusion of a gas is inversely proportional to the square root of its density.

i.e

$R \ \alpha \ \dfrac{1}{\sqrt{d}}$

$R = \dfrac{k}{d}$ where K = constant

If we compare the rate o diffusion of two gases;

$\dfrac{R_1}{R_2}= {\sqrt{\dfrac{d_2}{d_1}}$

Since the density of a gas d is proportional to its relative molecular mass M. Then;

$\dfrac{R_1}{R_2}= {\sqrt{\dfrac{M_2}{M_1}}$

Rate is the reciprocal of time ; i.e

$R = \dfrac{1}{t}$

Thus; replacing the value of R into the above previous equation;we have:

$\dfrac{R_1}{R_2}={\dfrac{t_2}{t_1}}$

We can equally say:

${\dfrac{t_2}{t_1}}= {\sqrt{\dfrac{M_2}{M_1}}$

${\dfrac{6.34}{4.98}}= {\sqrt{\dfrac{M_2}{32}}$

$M_2 = 32 \times ( \dfrac{6.34}{4.98})^2$

$M_2 = 32 \times ( 1.273092369)^2$

$M_2 = 32 \times 1.62076418$

$\mathbf{M_2 = 51.865 \ g/mol}$

7 0

3 years ago

Although cotton and wool are natural fibers, their production uses large quantities of water and other resources. Synthetic mate

lorasvet [3.4K]

C I think..........................

8 0

3 years ago

What happens in nuclear fushion

EleoNora [17]

Answer:

It gets squeeze together so tightly that four hydrogen nuclei combine to form one helium atom.

Explanation:

5 0

3 years ago

Experimental data have shown that the rate law for the reaction 2 hgcl2(aq) + c2o4 2 -(aq) → 2 cl-(aq) + 2 co2 (g) + hg2cl2 (s)

NNADVOKAT [17]

When the rate = K [ HgCl2] [C2O4 2-]^2
if the concentration of [ C2O4 2- ] is tripled so we will substitute by [3 (C2O4 2-)] instead of [ C2O4 2- ]
and if the concentration of [HgCl2] is doubled so we will substitute by [2( HgCl2)] instead of [HgCl2]
So the new rate will be = K [2(Hgcl2)] [3(C2O4 2-)]^2

6 0

4 years ago