Answer:
Below
Explanation:
The strength of Earth’s gravity decreases as an object gets farther from Earth. <===== this is the only statement that is true
Answer:
Exothermic Reaction
Explanation:
<u>ENDOTHERMIC REACTION</u>: A chemical reaction is considered endothermic if the energy is absorbed during the reaction. In other words, if the energy is required by the reactants to proceed with the reaction, then the reaction is endothermic.
The value of enthalpy change ΔH is positive in such reactions showing intake of energy.
<u>EXOTHERMIC REACTION</u>: A chemical reaction is considered exothermic if the energy is released during the reaction. In other words, if the energy is produced as a product of the reaction, then the reaction is exothermic.
The value of enthalpy change ΔH is negative in such reactions showing the release of energy.
Since, the value of ΔH = -125 KJ, is negative for the given reaction.
Therefore, it would be considered as <u>Exothermic Reaction.</u>
Answer:
a
The focal length of the lens in water is 
b
The focal length of the mirror in water is 
Explanation:
From the question we are told that
The index of refraction of the lens material = 
The index of refraction of the medium surrounding the lens = 
The lens maker's formula is mathematically represented as
![\frac{1}{f} = (n -1) [\frac{1}{R_1} - \frac{1}{R_2} ]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7Bf%7D%20%3D%20%28n%20-1%29%20%5B%5Cfrac%7B1%7D%7BR_1%7D%20-%20%5Cfrac%7B1%7D%7BR_2%7D%20%20%5D)
Where 
is the focal length
is the index of refraction
are the radius of curvature of sphere 1 and 2 of the lens
From the question When the lens in air we have
![\frac{1}{f_{air}} = (n-1) [\frac{1}{R_1} - \frac{1}{R_2} ]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7Bf_%7Bair%7D%7D%20%3D%20%28n-1%29%20%5B%5Cfrac%7B1%7D%7BR_1%7D%20-%20%5Cfrac%7B1%7D%7BR_2%7D%20%20%5D)
When immersed in liquid the formula becomes
![\frac{1}{f_{water}} = [\frac{n_2}{n_1} - 1 ] [\frac{1}{R_1} - \frac{1}{R_2} ]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7Bf_%7Bwater%7D%7D%20%3D%20%5B%5Cfrac%7Bn_2%7D%7Bn_1%7D%20-%201%20%5D%20%5B%5Cfrac%7B1%7D%7BR_1%7D%20-%20%5Cfrac%7B1%7D%7BR_2%7D%20%20%5D)
The ratio of the focal length of the the two medium is mathematically evaluated as
![\frac{f_water}{f_{air}} = \frac{n_2 -1}{[\frac{n_2}{n_1} - 1] }](https://tex.z-dn.net/?f=%5Cfrac%7Bf_water%7D%7Bf_%7Bair%7D%7D%20%3D%20%5Cfrac%7Bn_2%20-1%7D%7B%5B%5Cfrac%7Bn_2%7D%7Bn_1%7D%20-%201%5D%20%7D)
From the question
= 79.0 cm
and the refractive index of water(material surrounding the lens) has a constant value of 
b
The focal length of a mirror is dependent on the concept of reflection which is not affected by medium around it.
Answer:
false
Explanation:
every object will always have the force of gravity acting upon it.
Answer:
τ ≈ 0.90 N•m
F =
Explanation:
I = ½mR² = ½(10)0.5² = 1.25 kg•m²
α = ω²/2θ = 3.0² / 4π = 0.716... rad/s²
τ = Iα = 1.25(0.716) = 0.8952... ≈ 0.90 N•m
τ = FR
Now we have the unanswered question of reference frame.
80° from what?
If it's 80° from the radial
F = τ/Rsinθ = 0.90/0.5sin80 = 1.818... ≈ 1.8 N
If it's If it's 80° from the tangential
F = τ/Rcosθ = 0.90/0.5cos80 = 10.311... ≈ 10 N
There are an infinite number of other potential solutions
