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Reika [66]
3 years ago
10

Who invented the first practical incandescent light bulb?.

Physics
1 answer:
OverLord2011 [107]3 years ago
6 0

Answer:

Edison

Explanation:

Among other notable inventions, Edison and his assistants developed the first practical incandescent lightbulb in 1879 and a forerunner of the movie camera and projector in the late 1880s.

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The wavelength corresponding to light with a frequency of 4 x 10^14 Hz is 1.33m 0.075 mm 7500 nm 750 nm
Scorpion4ik [409]

Answer:

Wavelength of light is 750 nm.

Explanation:

It is given that,

Frequency of light, \nu=4\times 10^{14}\ Hz

The relationship between the wavelength and the frequency of light is given by :

c=\nu\times \lambda

Where

c = speed of light

\nu = frequency of light

\lambda = wavelength of light

\lambda=\dfrac{c}{\nu}

\lambda=\dfrac{3\times 10^8\ m/s}{4\times 10^{14}\ Hz}

\lambda=7.5\times 10^{-7}\ m

\lambda=750\ nm

Hence, the correct option is (d) "750 nm".

7 0
4 years ago
A girl jogs around a horizontal circle with a constant speed. She travels one fourth of a revolution, a distance of 25 m along t
Rus_ich [418]

Answer:

The centripetal acceleration of the girl is 2.468 m/s²

Explanation:

Given;

number of turns, = ¹/₄ Revolution

distance traveled by the girl, d = 25 m

time of motion, t = 5.0 s

The linear speed of the of the girl is calculated as;

v = \omega \ r\\\\v =(\frac{1}{4}rev \times \frac{2\pi \ rad}{1 \ rev} \times \frac{1}{5 \ s} )  (25 \ m)\\\\v =  (0.3142 \ \frac{rad}{s} )(25 \ m)\\\\v = 7.855 \ m/s

The centripetal acceleration of the girl is calculated as;

a_c = \frac{v^2}{r} \\\\a_c = \frac{(7.855)^2}{25} \\\\a_c = 2.468 \ m/s^2

Therefore, the centripetal acceleration of the girl is 2.468 m/s²

8 0
3 years ago
What is a force that does not involve physical contact between two objects?
Norma-Jean [14]
<span>a force that does not involve physical contact between two objects ic called field force.</span>
5 0
4 years ago
Read 2 more answers
A loop of area 0.250 m^2 is in a uniform 0.020 0-T magnetic field. If the flux through the loop is 3.83 × 10-3T· m2, what angle
Nostrana [21]

Answer:

40.0⁰

Explanation:

The formula for calculating the magnetic flux is expressed as:

\phi = BAcos\theta where:

\phi is the magnetic flux

B is the magnetic field

A is the cross sectional area

\theta is the angle that the normal to the plane of the loop make with the direction of the magnetic field.

Given

A = 0.250m²

B = 0.020T

\phi = 3.83 × 10⁻³T· m²

3.83 × 10⁻³ = 0.020*0.250cosθ

3.83 × 10⁻³ = 0.005cosθ

cosθ = 0.00383/0.005

cosθ = 0.766

θ = cos⁻¹0.766

θ = 40.0⁰

<em>Hence the angle normal to the plane of the loop make with the direction of the magnetic field is 40.0⁰</em>

6 0
3 years ago
During development, the cells in these organisms become specialized.
Y_Kistochka [10]

Answer:

A- multicellular

Explanation:

fertilized egg I think that is the answer

7 0
3 years ago
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