Answer:
The displacement of the car after 6s is 43.2 m
Explanation:
Given;
velocity of the car, v = 12 m/s
acceleration of the car, a = -1.6 m/s² (backward acceleration)
time of motion, t = 6 s
The displacement of the car after 6s is given by the following kinematic equation;
d = ut + ¹/₂at²
d = (12 x 6) + ¹/₂(-1.6)(6)²
d = 72 - 28.8
d = 43.2 m
Therefore, the displacement of the car after 6s is 43.2 m
Explanation:
One mile equals 1609.344 meters
This is called a reference point
Answer:
a. 5.360m/s
b. -1.1m/s
c. 3.38m/s
Explanation:
V1 = 3.20j
V2 = 4.30i
Vp = 5.4(-i)
= -5.40i
a. Speed of boat 2 relative to shore
= v1 + v2
= 3.2j + 4.3i
Magnitude = √3 2²+4.3²
= √28.73
= 5.360m/s
b. Speed of passenger relative to boat 1
V(p,1) = vp + v2
= -5.40i + 4.3i
= -1.1m/s
c. Speed of passenger relative to share
V(p,s) = vp + v(2,s)
= -5.4i + 4.30i +3.2j
= -1.1i + 3.2j
Take magnitude
= √-1.1²+3.2²
= √ 1.21 +10.24
= √11.45
= 3.38m/s
When light changes the medium it travels through it also changes speed. The speed in medium is given by formula:
Rearranging formual gives:
From this formula we can make conclusion that index of refraction is inversely proportional to speed of light in medium. This means that greater speed gives smaller index of refraction.