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rusak2 [61]
3 years ago
8

There are several houses for sale in a local neighborhood. One house is on the market for $105,000. Four houses are on sale for

$175,000. Six houses are on sale for $199,900, and another house is on the market for $700,000. Which of the following measures of central tendency best represents the market value of a house in that neighborhood?
Mathematics
1 answer:
abruzzese [7]3 years ago
8 0
600,457 is correct answer
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Examine the following equation and classify the type of solution.
Viktor [21]

Answer:

<h2>infinitely many solutions</h2>

Step-by-step explanation:

5x - 6 = 3x - 6 + 2x     <em>combine like terms</em>

5x - 6 = (3x + 2x) - 6

5x - 6 = 5x - 6         <em>subtract 5x from both sides</em>

-6 = -6        TRUE

Therefore the equation has infinitely many solutions.

5 0
3 years ago
3 times a number xx, subtracted from 1818, is less than -90.?90. Write an inequality for the statement above. Find the solution
Evgen [1.6K]

Answer:

The solution set is: x>36

Step-by-step explanation:

We are given that we have to subtract 3 times of some number 'x' from 18 such that the resulting equation is less than -90.

this means that : 18-3x<-90

on solving the inequality by adding 3x on both side and adding 90 on both side we get that

 108<3x

now on dividing both side by 3 we get that

x>36

Hence our solution set is: x>36


5 0
3 years ago
Read 2 more answers
Helpppppppppp<br> Urgenttttt<br> Pleaseeeee!
Alika [10]

Answer:

The first set is a set of linear equations.

The way to figure this out is pretty easy. If you want to see it visually, go search up desmos graphing calculator and put in these equations.

A linear equation is a function that has a constant slope, meaning that the rate it increases or decreases will never change. The first one is a set of linear equations because it is 2 equations with constant slopes, meaning that the slopes will never change no matter what y and x are.

The second set is not, because while the first equation is linear, the second is an inequality. While it is a straight line, it doesn't count as a linear equation.

The third set, both equations have exponents on the x, which means that the slope will change depending on x. This means that both of these are not linear equations.

The only set that is a linear set is the one that has only linear equations.

3 0
1 year ago
The weight of an organ in adult males has a bell-shaped distribution with a mean of 310 grams and a standard deviation of 25 gra
Shkiper50 [21]

Answer:

About 68% of organs will be between 300 grams and 320 grams, about 95% of organs will be About 68% of organs will be between 300 grams and 320 grams, About 68% of organs will be between 300 grams and 320 grams, about 95% of organs will be between 280 grams and 360 grams, the percentage of organs weighs less than 280 grams or more than 360 grams is 5%, and the percentage of organs weighs between 300 grams and 360 grams is 81.5%.

Given :

The weight of an organ in adult males has a bell-shaped distribution with a mean of 320 grams and a standard deviation of 20 grams.

A) According to the empirical rule, using the values of mean and standard deviation:

\rm \mu-\sigma = 320-20=300 \; gramsμ+σ=320+20=320grams

Therefore, about 68% of organs will be between 300 grams and 320 grams.

B) Again according to the empirical rule, using the values of mean and standard deviation:

\rm \mu-2\times \sigma = 320-40=280 \; gramsμ−2×σ=320−40=280grams

\rm \mu+2\times \sigma = 320+40=360 \; gramsμ+2×σ=320+40=360grams

Therefore, according to the empirical rule, about 95% of organs will be between 280 grams and 360 grams.

C)

The percentage of organs weighs less than 280 grams or more than 360 grams = 100 - (The percentage of organs weighs between 280 grams and 360 grams)

The percentage of organs weighs less than 280 grams or more than 360 grams = 100 - 95 = 5%

D)

The percentage of organs weighs between 300 grams and 360 grams = 0.5 \times× ( percentage of organs weighs between 280 grams and 360 grams + percentage of organs weighs between 300 grams and 320 grams)

The percentage of organs weighs between 300 grams and 360 grams = 0.5 \times× (95 + 68)

So, the percentage of organs weighing between 300 grams and 360 grams is 81.5%.

For more information, refer to the link given below:

brainly.com/question/23017717 95% of organs will be between 280 grams and 360 grams, the percentage of organs weighs less than 280 grams or more than 360 grams is 5%, and the percentage of organs weighs between 300 grams and 360 grams is 81.5%.

Given :

The weight of an organ in adult males has a bell-shaped distribution with a mean of 320 grams and a standard deviation of 20 grams.

A) According to the empirical rule, using the values of mean and standard deviation:

\rm \mu-\sigma = 320-20=300 \; gramsμ−σ=320−20=300grams

\rm \mu+\sigma = 320+20=320 \; gramsμ+σ=320+20=320grams

Therefore, about 68% of organs will be between 300 grams and 320 grams.

B) Again according to the empirical rule, using the values of mean and standard deviation:

\rm \mu-2\times \sigma = 320-40=280 \; gramsμ−2×σ=320−40=280grams

\rm \mu+2\times \sigma = 320+40=360 \; gramsμ+2×σ=320+40=360grams

Therefore, according to the empirical rule, about 95% of organs will be between 280 grams and 360 grams.

C)

The percentage of organs weighs less than 280 grams or more than 360 grams = 100 - (The percentage of organs weighs between 280 grams and 360 grams)

The percentage of organs weighs less than 280 grams or more than 360 grams = 100 - 95 = 5%

D)

The percentage of organs weighs between 300 grams and 360 grams = 0.5 \times× ( percentage of organs weighs between 280 grams and 360 grams + percentage of organs weighs between 300 grams and 320 grams)

The percentage of organs weighs between 300 grams and 360 grams = 0.5 \times× (95 + 68)

So, the percentage of organs weighing between 300 grams and 360 grams is 81.5%.

For more information, refer to the link given below:

brainly.com/question/23017717

5 0
2 years ago
A large truck has two fuel tanks, each with a capacity of 150 gallons. Tank 1 is half full, and Tank 2 is empty.
12345 [234]

Answer:

1) G(t) = 75 + \frac{23}{4}t\\

2) After 8 minutes delivering fuel the tanks will have 121 gallons of fuel

Step-by-step explanation:

1) For generating the equation we have to take into account that in the tanks there is a initial volume of fuel that corresponds to 75 gallons, as it is stated that tank one is half full. As the capacity for tank 1 is of 150 gallons, half of the tank equals to:

\frac{150}{2} = 75 gallons

Now we have to convert the rate of delivery that is expressed as a mixed number to an improper fraction so:

5\frac{3}{4} = \frac{(5x4)+3}{4} = \frac{23}{4}

Then the pumping rate is of 23/4 gallons per minute, to get how many gallons are in the tank we just need to multiply this rate by the time in minutes, and as there is an initial volume we have to add it, so we have the following equation:

G(t) = 75 + \frac{23}{4}t\\

2) To know how much fuel is in the tank after 8 minutes we have to replace this time in the previous equation so we have

G(t) = 75 + \frac{23}{4}t\\G(8) = 75 + \frac{23}{4}(8)\\G(8) = 75 + 23(2)\\G(8) = 75 + 46\\G(8) = 121 gallons

After 8 minutes delivering fuel the tanks will have 121 gallons of fuel

8 0
3 years ago
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