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4 years ago

Use DeMorgan's laws to write a negation for the statement "the Hulk is green or the Iron Man is red"

Mathematics

1 answer:

erastova [34]4 years ago

7 0

Answer:

"The Hulk is not green AND the Iron Man is not red"

Step-by-step explanation:

DeMorgan's laws state that the negation of an statement whose structure is "p OR q" is "not p AND not q", and similarly, that the negation of an statement whose structure is "p AND q" is "not p OR not q". The statement we want to negate in our case is "The Hulk is green OR the Iron Man is red". This is an statement whose structure is of the type "p OR q", where p would be "The Hulk is green", and q would be "the Iron Man is red". So according to DeMorgan's laws, its negation should be the statement "not p AND not q". To put them in common english, not p would be "The Hulk is NOT green", and not q would be "The Iron Man is NOT red". So the statement "not p AND not q" is simply "The Hulk is not green AND the Iron Man is not red".

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A boy walks 58 feet up a ramp having a 22.5 degree inclination. how high is he standing from the ground?

yKpoI14uk [10]

Boy is 22.5 feet high from the ground

The six trigonometric ratios are sine (sin), cosine (cos), tangent (tan), cotangent (cot), cosecant (cosec), and secant (sec). In geometry, trigonometry is a branch of mathematics that deals with the sides and angles of a right-angled triangle. Therefore, trig ratios are evaluated with respect to sides and angles.

The given question can be solved by sin, as value of perpendicular is to be evaluated and height and angle is provided. Let height from the ground be x

sin(22.5°) = x / 58

x = 58sin22.5 = 58(.38258) = 22.5 feet high.

Thus the Boy is 22.5 feet high from the ground.

Learn more about trigonometry here :

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2 years ago

In one city, 3,546 people attended a concert but in another city, 9,238 people attended the same band's concert. Estimate how ma

Angelina_Jolie [31]

The answer is 5,7000

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3 years ago

Please help me with algebra part B and C. attachment below. Will mark as brainslist. 25 points.

miv72 [106K]

Answer:

C. $(-7x+60)(x+4)$

Step-by-step explanation:

Consider the expression $-7x^2+32x+240.$

First, note that

$a=-7\\ \\b=32\\ \\c=240$

Find the discriminant

$D=b^2-4ac=32^2-4\cdot (-7)\cdot 240=1,024+6,720=7,744\\ \\\sqrt{D}=\sqrt{7,744}=88$

Now,

$x_1=\dfrac{-b+\sqrt{D}}{2a}=\dfrac{-32+88}{2\cdot (-7)}=-4\\ \\x_2=\dfrac{-b-\sqrt{D}}{2a}=\dfrac{-32-88}{2\cdot (-7)}=\dfrac{60}{7}$

Write the factored form:

$-7x^2+32x+240=-7(x-(-4))\left(x-\dfrac{60}{7}\right)=(x+4)(-7x+60)$

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3 years ago

Write each number in expanded form and using number names.

stellarik [79]

1. 20,000 +7,000 +500 +40 +9 -----WORD FORM :twenty-seven thousand,
five hundred forty-nine

2. Expanded Numbers Form:

 700,000 +90,000 +2,000 +0 +60 +5 
WORD FORM : seven hundred ninety-two thousand,
sixty-five

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3 years ago

It’s a new semester! Students are grouped into three clubs, which each has 10, 4 and 5 students. In how many ways can teacher se

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Here we must see in how many different ways we can select 2 students from the 3 clubs, such that the students do not belong to the same club. We will see that there are 110 different ways in which 2 students from different clubs can be selected.

So there are 3 clubs:

Club A, with 10 students.
Club B, with 4 students.
Club C, with 5 students.

The possible combinations of 2 students from different clubs are

Club A with club B
Club A with club C
Club B with club C.

The number of combinations for each of these is given by the product between the number of students in the club, so we get:

Club A with club B: 10*4 = 40
Club A with club C: 10*5 = 50
Club B with club C. 4*5 = 20

For a total of 40 + 50 + 20 = 110 different combinations.

This means that there are 110 different ways in which 2 students from different clubs can be selected.

If you want to learn more about combination and selections, you can read:

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2 years ago