An expressiom with an exponent that has a value between 0 and 1

Can someone help me.

Alex

I’m sorry I don’t know

3 0

3 years ago

What is the sum? StartFraction 3 Over x squared minus 9 EndFraction StartFraction 5 Over x 3 EndFraction.

V125BC [204]

The sum of the two fractional number, which consist in the variable <em>x</em> is in the polynomial function,

$f(x)=\dfrac{5x-12}{(x+3)(x-3)}$

<h3>What is the sum of fraction number?</h3>

Fraction number is the number which is a part of a whole number. It is written with a numerator and denominator.

Fraction number are written as,

$\dfrac{a}{b}$

Here (a) is the numerator and (b) is the denominator.

To find the sum of two fraction numbers, cross multiply both the numbers or find the least common factor as denominator.

The first fraction number given in the problem is,

$\dfrac{3}{x^2+9}$

The second fraction number given in the problem is,

$\dfrac{5}{x+3}$

Let the sum of these number is f(x). Thus,

$f(x)=\dfrac{3}{x^2-9}+\dfrac{5}{x+3}\\f(x)=\dfrac{3}{(x+3)(x-3)}+\dfrac{5}{x+3}\\$

Solve it further as,

$f(x)=\dfrac{3+5(x-3)}{(x+3)(x-3)}\\f(x)=\dfrac{3+5x-15}{(x+3)(x-3)}\\f(x)=\dfrac{5x-12}{(x+3)(x-3)}$

Thus, the sum of the two fractional number is,

$f(x)=\dfrac{5x-12}{(x+3)(x-3)}$

Learn more about the fraction number here:

brainly.com/question/78672

6 0

2 years ago

49x^2 -_x + 16<br><br> Can someone help with the missing number

mihalych1998 [28]

Step-by-step explanation:

I'm guessing this is competing the perfect square

so it's 56

5 0

3 years ago

Read 2 more answers

Match the y-coordinate with the given x-coordinate for the equation y = log10x.

Andrew [12]

The non-algebraic functions are called transcendental functions. This include the logarithmic function. The definition of Logarithmic Function with Base a is as follows:

$For \ x\ \textgreater \ 0, \ a \ \textgreater \ 0, \ and \ a \neq 1 \\ \\ y=log_{a}x \ if \ and \ only \ if \ x=a^{y} \\ \\ Then: \\ \\ f(x)=log_{a}x \\ \\ is \ called \ the \ logarithmic \ function \ with \ base \ a.$

We know that the equations is:

$y=log(10x)$

So let's solve each case:

Case 1

$x=\frac{1}{100} \\ \\ y=log(10(\frac{1}{100})) \\ \\ \therefore y=log(\frac{1}{10}) \\ \\ \therefore y=-1 \\ \\ So: \\ \\ \boxed{\ x=\frac{1}{100}} \ matches \ to \ \boxed{y=-1}$

Case 2

$x=\frac{1}{10} \\ \\ y=log(10(\frac{1}{10})) \\ \\ \therefore y=log(1) \\ \\ \therefore y=0 \\ \\ So: \\ \\ \boxed{\ x=\frac{1}{10}} \ matches \ to \ \boxed{y=0}$

Case 3

$x=1 \\ \\ y=log(10(1)) \\ \\ \therefore y=log(10) \\ \\ \therefore y=1 \\ \\ So: \\ \\ \boxed{\ x=1} \ matches \ to \ \boxed{y=1}$

Case 4

$x=10 \\ \\ y=log(10(10)) \\ \\ \therefore y=log(100) \\ \\ \therefore y=2 \\ \\ So: \\ \\ \boxed{\ x=10} \ matches \ to \ \boxed{y=2}$

Case 5

$x=100 \\ \\ y=log(10(100)) \\ \\ \therefore y=log(1000) \\ \\ \therefore y=3 \\ \\ So: \\ \\ \boxed{x=100} \ matches \ to \ \boxed{y=3}$

5 0

4 years ago

Read 2 more answers

Angle DEB is 42. State the size of angle ABD

Kay [80]

Answer:

The answer would be 80 ° because 5×( 2 + 13 or x +1 ) is 80

Step-by-step explanation:

ABD is 80°

If DEB is 42 °

∠ ABD = 5(2X+1)

∠ DBC = 3X+6

∠ EBC = Y +135/2

∠ ABD and ∠ DBC are linear pairs

∴ ∠ ABD +∠ DBC = 180

∴ 5(2X+1) + 3X+6 =180

solve for x

∴ x = 13

∴∠ ABD = 5(2X+1) = 5(2*13+1) = 135

∠ DBC = 3x+6 = 3*13+6 = 45

∠ ABD and ∠ EBC are vertical angles

∴ ∠ ABD = ∠ EBC = 135

∴ y +135/2 = 135

∴ y = 135/2

5 0

3 years ago