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3 years ago

Which chemical is produced during vigorous exercise when the supply of oxygen is limited or inadequate?

1 answer:

4 0

It is lactic acid the chemical is produced during vigorous exercise when the supply of oxygen is limited or inadequate. <span> It forms when the body breaks down carbohydrates to use for energy during times of low oxygen levels. Hope this answers the question. Have a nice day.</span>

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How many grams of carbonic acid were produced by the 3.00g sample of NaHCO3

Alexxx [7]

I dont know what subject is this

8 0

2 years ago

as the elements period 3 are considered in order of increasing atomic number, the number of principal energy levels in each succ

Diano4ka-milaya [45]

Answer:

stay the same.

Explanation: Period 3 consists of the full 1s, 2s, and 2p electron orbitals, plus the 3s and 3p valence orbitals, which are filled with a total of 8 more electrons as we move from left (Na) to the far right (Ar):

Na: 1s2 2s2 2p6 3s1

Ar: s2 2s2 2p6 3s2 3p6

As we move from left to right, and ignoring the already-filled 1s, 2s, and 2p orbitals, the period three starting and ending elements have the following:

Na: 3s1

Ar: 3s2, 3p6

All the new electrons electrons filled the third energy level (3s and 3p). So the energy level does not change, just the orbitals.

5 0

2 years ago

The energy E of the electron in a hydrogen atom can be calculated from the Bohr formula: E = R_y/n^2 In this equation R_y stands

Katarina [22]

Answer:

The wavelength of the line in the emission line spectrum of hydrogen caused by the transition of the electron for the given energy levels is $5.23\times 10^{-5} m$

Explanation:

Given :

The energy E of the electron in a hydrogen atom can be calculated from the Bohr formula:

$E=\frac{R_y}{n^2}$

$R_y=2.18\times 10^{-18} J$ = Rydberg energy

n = principal quantum number of the orbital

Energy of 11th orbit = $E_{11}$

$E_{11}=\frac{2.18\times 10^{-18} J}{11^2}=1.80\times 10^{-20} J$

Energy of 10th orbit = $E_{10}$

$E_{10}=\frac{2.18\times 10^{-18} J}{10^2}=2.18\times 10^{-20} J$

Energy difference between both the levels will corresponds to the energy of the wavelength of the line which can be calculated by using Planck's equation.

$E'=E_{10}-E_{11}=2.18\times 10^{-20} J-1.80\times 10^{-20} J$

$=E'=0.38\times 10^{-20} J$

$\lambda =\frac{hc}{E'}$ (Planck's' equation)

$\lambda = \frac{6.626\times 10^{-34} Js\times 3\times 10^8 m/s}{0.38\times 10^{-20} J}$

$\lambda = 5.2310\times 10^{-5} m\approx 5.23\times 10^{-5} m$

The wavelength of the line in the emission line spectrum of hydrogen caused by the transition of the electron for the given energy levels is $5.23\times 10^{-5} m$

3 0

2 years ago

Linus pauling is famous for?

Sloan [31]

Answer:

Linus Pauling became known as the founder of molecular biology due to his discovery of the spiral structure of proteins (Taton, 1964)

Explanation:

3 0

2 years ago

Predict the following chemical formula for a compound between aluminum and chlorine. AlCl3 Al3Cl Al2Cl3 Al3Cl2

Tasya [4]

Both aluminum and chlorine have known charges, which are +3 and -1 respectively. To make them cancel each other out in charge, you would need 3 chlorine and for one aluminum, therefore $AlCl_{3}$ would be correct

7 0

2 years ago