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Rzqust [24]
2 years ago
7

How many grams of CaO can be produced using 3.9 moles CaCO3?1 CaCO3 --> 1CaO + 1CO *

Chemistry
1 answer:
Lina20 [59]2 years ago
4 0

Answer: 218.4 g of CaO will be produced from 3.9 moles of CaCO_3

Explanation:

The balanced chemical equation is:

CaCO_3\rightarrow CaO+CO_2  

According to stoichiometry :

1 mole of CaCO_3 produce =  1 mole of CaO

Thus 3.9 moles of CaCO_3 will produce=\frac{1}{1}\times 3.9=3.9moles of CaO

Mass of CaO=moles\times {\text {Molar mass}}=3.9moles\times 56g/mol=218.4g

Thus 218.4 g of CaO will be produced from 3.9 moles of CaCO_3

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