Question

How many grams of CaO can be produced using 3.9 moles CaCO3?1 CaCO3 --> 1CaO + 1CO *

Answer 1

Answer: 218.4 g of $CaO$ will be produced from 3.9 moles of $CaCO_3$

Explanation:

The balanced chemical equation is:

$CaCO_3\rightarrow CaO+CO_2$  

According to stoichiometry :

1 mole of $CaCO_3$ produce =  1 mole of $CaO$

Thus 3.9 moles of $CaCO_3$ will produce=$\frac{1}{1}\times 3.9=3.9moles$ of $CaO$

Mass of $CaO=moles\times {\text {Molar mass}}=3.9moles\times 56g/mol=218.4g$

Thus 218.4 g of $CaO$ will be produced from 3.9 moles of $CaCO_3$