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nikitadnepr [17]
3 years ago
6

Na S (1) + CdNO3 (1) ➡️ Cds (s) + 2 NaNO3 (1) is which type of reaction?

Chemistry
1 answer:
DaniilM [7]3 years ago
7 0

a) double-displacement

Explanation:

We have the following chemical reaction:

Na₂S (aq) + Cd(NO₃)₂ (aq) → CdS (s) + 2 NaNO₃ (aq)

where:

(aq) - aqueous

(s) - solid

This chemical reaction is a double-displacement reaction because the reactant exchange atoms or group of atoms between themselves. The reaction is driven to right by the formation of the precipitate. The general representation for this kind of reaction is: AB + CD → AC + BD

In a synthesis reaction two elements will combine to form a compound.

2 H₂ + O₂ → 2 H₂O

In a single-displacement reaction an atom or group of atoms from a compound is displaced by another atoms. The general representation for this kind of reaction is: A + BC → B + AC

Learn more about:

type of chemical equations

brainly.com/question/13804942

#learnwithBrainly

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How many molecules of CaCl2 are equivalent to 75.9 g CaCl2
sergij07 [2.7K]
First, you need to find:
One mole of CaCl_{2} is equivalent to how many grams?

Well, for this you have to look up the periodic table. According to the periodic table:
The atomic mass of Calcium Ca = 40.078 g (See in group 2)
The atomic mass of <span>Chlorine Cl = 35.45 g (See in group 17)
</span>
As there are two atoms of Chlorine present in CaCl_{2}, therefore, the atomic mass of CaCl_{2} would be:

Atomic mass of CaCl_{2}  = Atomic mass of Ca + 2 * Atomic mass of Cl

Atomic mass of CaCl_{2} = 40.078 + 2 * 35.45 = 110.978 g

Now,

110.978 g of CaCl_{2} = 1 mole.
75.9 g of CaCl_{2} = \frac{75.9}{110.978} moles = 0.6839 moles.

Hence,
The total number of moles in 75.9g of CaCl_{2} = 0.6839 moles

According to <span>Avogadro's number,
1 mole = 1 * </span>6.022 * 10^{23} molecules
0.6839 moles = 0.6839 * 6.022 * 10^{23} molecules = 4.118*10^{23} molecules

Ans: Number of molecules in 75.9g of  CaCl_{2} =  4.118*10^{23} molecules

-i


3 0
3 years ago
Read 2 more answers
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