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nikitadnepr [17]
3 years ago
6

Na S (1) + CdNO3 (1) ➡️ Cds (s) + 2 NaNO3 (1) is which type of reaction?

Chemistry
1 answer:
DaniilM [7]3 years ago
7 0

a) double-displacement

Explanation:

We have the following chemical reaction:

Na₂S (aq) + Cd(NO₃)₂ (aq) → CdS (s) + 2 NaNO₃ (aq)

where:

(aq) - aqueous

(s) - solid

This chemical reaction is a double-displacement reaction because the reactant exchange atoms or group of atoms between themselves. The reaction is driven to right by the formation of the precipitate. The general representation for this kind of reaction is: AB + CD → AC + BD

In a synthesis reaction two elements will combine to form a compound.

2 H₂ + O₂ → 2 H₂O

In a single-displacement reaction an atom or group of atoms from a compound is displaced by another atoms. The general representation for this kind of reaction is: A + BC → B + AC

Learn more about:

type of chemical equations

brainly.com/question/13804942

#learnwithBrainly

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A stone is dropped from the roof of a building; 2.00s after that, a second stone is thrown straight down with an initial speed o
Brut [27]
A) -0.5(9.8)*t^2 = -25(t-2) - 0.5(9.8)(t-2)^2 
-4.9t^2 = -25t + 50 - 4.9(t^2-4t+4) 
0 = -25t+50+19.6t - 19.6 
5.4t = 30.4 
t = 5.62962963 s 

b) h = -4.9(5.62962963)^2 
h = -155.2943759 
the building is 155.2943759 m high 

c) speed 0of first stone 
= at 
= 9.8*5.62962963 
= 55.17037037 m/s 
speed of second stone
= v + at
= 25+9.8*3.62962963 
= 60.57037037 m/s
7 0
3 years ago
why was the mass lost when the reaction was done in the normal setup but stayed the same when it was done in the gas collection
german
<h2>Answer : Law of conservation of mass</h2><h3>Explanation :</h3>

The law of conservation of mass states that in any reaction mass is neither created nor lost it has to remain constant in a system.

In this case, when the reaction setup was done in normal way the mass was  lost in surrounding was not considered nor being calculated; whereas when the reaction was studied in a closed system where the gas was collected after the reaction the mass changes was noted down which helped to prove the point of law of conservation of mass and energy.

One can consider an example of soda can where the carbonated drink contains pressurized carbon dioxide gas. when opened the gas bubbles gets lost into the surroundings and we don't measure the mass changes. Instead if the soda can was opened in such a way where the gas evolved was measured then the mass changed would remain the same.

6 0
3 years ago
A marble is sitting motionless on a table. How can you make it move?
Salsk061 [2.6K]
You can pick it up and move it
8 0
3 years ago
Read 2 more answers
A chemist has 2. 0 mol of methanol (CH3OH). The molar mass of methanol is 32. 0 g/mol. What is the mass, in grams, of the sample
natima [27]

The mass, in grams, of the sample of methanol (CH₃OH) is 64 grams.

<h3>How we calculate mass from moles?</h3>

Mass of any substance can be calculated by using moles as:

n = W/M, where

W = required mass

M = molar mass

In the question that:

Moles of methanol = 2mole

Molar mass of methanol = 32g/mole

On putting these values in the above equation, we get

W = n × M

W = 2mole × 32g/mole = 64g

Hence, 64 grams is the mass of the sample.

To know more about moles, visit the below link:

brainly.com/question/15374113

6 0
3 years ago
PLEASE HELP!!!
trasher [3.6K]

Answer:

(a) oxygen

(b) 154g (to 3sf)

(c) 79.9% (to 3sf)

Explanation:

mass (g) = moles × Mr/Ar

note: eqn means chemical equation

(a)

moles of P = 84.1 ÷ 30.973 = 2.7152 moles

moles of O2 = 85÷2(16) = 2.65625 moles

Assuming all the moles of P is used up,

moles of O2 / moles of phosphorus = 5/4 (according to balanced chemical eqn)

moles of O2 required = 5/4 × 2.7152moles = 3.394 moles (more than supplied which is 2.65625moles)

therefore there is insufficient moles of O2 and the limiting reactant is oxygen.

(b)

moles of P2O5 produced

= 2/5 (according to eqn) × 2.7152

= 1.08608moles

mass of P2O5 produced

= 1.08608 × [ 2(30.973) + 5(16) ]

= 154.164g

= approx. 154g to 3 sig. fig.

(c)

% yield = actual/theoretical yield × 100%

= 123/154 × 100%

= 79.870%

= approx. 79.9% (to 3sf)

4 0
3 years ago
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