Answer:
4.09×10⁻³ is the mole fraction of sucrose
Explanation:
Mole fraction = Moles of solute or solvent/ Total moles
Let's convert the mass to moles (mass / molar mass)
38.6 g / 342 g/m = 0.113 moles of sucrose
495 g / 18 g/m = 27.5 moles of water
Total moles = 0.113 m + 27.5 m = 27.0613 moles
Mole fraction of sucrose = Moles of sucrose / Total moles
0.113 m / 27.0613 moles = 4.09×10⁻³
Answer:
86.0 mL
Explanation:
i just did the USA test prep
Explanation:
According to the given data, we will calculate the following.
Half life of lipase
= 8 min x 60 s/min
= 480 s
Rate constant for first order reaction is as follows.
=
Initial fat concentration
= 45
= 45 mmol/L
Rate of hydrolysis
= 0.07 mmol/L/s
Conversion X = 0.80
Final concentration (S) =
= 45 (1 - 0.80)
= 9
or, = 9 mmol/L
It is given that
= 5mmol/L
Therefore, time taken will be calculated as follows.
t = ![-\frac{1}{K_{d}}ln[1 - \frac{K_{d}}{V}{K_{M} ln (\frac{S_{o}}{S}) + (S_{o} - S)]](https://tex.z-dn.net/?f=-%5Cfrac%7B1%7D%7BK_%7Bd%7D%7Dln%5B1%20-%20%5Cfrac%7BK_%7Bd%7D%7D%7BV%7D%7BK_%7BM%7D%20ln%20%28%5Cfrac%7BS_%7Bo%7D%7D%7BS%7D%29%20%2B%20%28S_%7Bo%7D%20-%20S%29%5D)
Now, putting the given values into the above formula as follows.
t =
= ![-\frac{1}{1.44 \times 10^{-3}s^{-1}}ln[1 - \frac{1.44 \times 10^{-3}s^{-1}}{0.07 mmol/L/s }{K_{M} ln (\frac{45 mmol/L }{9 mmol/L }) + (45 mmol/L - 9 mmol/L )]](https://tex.z-dn.net/?f=-%5Cfrac%7B1%7D%7B1.44%20%5Ctimes%2010%5E%7B-3%7Ds%5E%7B-1%7D%7Dln%5B1%20-%20%5Cfrac%7B1.44%20%5Ctimes%2010%5E%7B-3%7Ds%5E%7B-1%7D%7D%7B0.07%20mmol%2FL%2Fs%0A%7D%7BK_%7BM%7D%20ln%20%28%5Cfrac%7B45%20mmol%2FL%0A%7D%7B9%20mmol%2FL%0A%7D%29%20%2B%20%2845%20mmol%2FL%20-%209%20mmol%2FL%0A%29%5D)
= ![1642.83 s \times \frac{1 min}{60 sec}](https://tex.z-dn.net/?f=1642.83%20s%20%5Ctimes%20%5Cfrac%7B1%20min%7D%7B60%20sec%7D)
= 27.38 min
Therefore, we can conclude that time taken by the enzyme to hydrolyse 80% of the fat present is 27.38 min.
Answer: An ionic bond is a type of chemical bond formed through an electrostatic attraction between two oppositely charged ions. Ionic bonds are formed between a cation, which is usually a metal, and an anion, which is usually a nonmetal.
basically explains
Answer : The energy of the photon emitted is, -12.1 eV
Explanation :
First we have to calculate the
orbit of hydrogen atom.
Formula used :
![E_n=-13.6\times \frac{Z^2}{n^2}ev](https://tex.z-dn.net/?f=E_n%3D-13.6%5Ctimes%20%5Cfrac%7BZ%5E2%7D%7Bn%5E2%7Dev)
where,
= energy of
orbit
n = number of orbit
Z = atomic number of hydrogen atom = 1
Energy of n = 1 in an hydrogen atom:
![E_1=-13.6\times \frac{1^2}{1^2}eV=-13.6eV](https://tex.z-dn.net/?f=E_1%3D-13.6%5Ctimes%20%5Cfrac%7B1%5E2%7D%7B1%5E2%7DeV%3D-13.6eV)
Energy of n = 2 in an hydrogen atom:
![E_3=-13.6\times \frac{1^2}{3^2}eV=-1.51eV](https://tex.z-dn.net/?f=E_3%3D-13.6%5Ctimes%20%5Cfrac%7B1%5E2%7D%7B3%5E2%7DeV%3D-1.51eV)
Energy change transition from n = 1 to n = 3 occurs.
Let energy change be E.
![E=E_-E_3=(-13.6eV)-(-1.51eV)=-12.1eV](https://tex.z-dn.net/?f=E%3DE_-E_3%3D%28-13.6eV%29-%28-1.51eV%29%3D-12.1eV)
The negative sign indicates that energy of the photon emitted.
Thus, the energy of the photon emitted is, -12.1 eV