It is true that the major ways people are exposed to toxins are by ingesting them, inhaling them, injecting them, or absorbing them through the skin.

Explanation:

Toxins can enter in four various ways into our body often referred as "route of exposure". It is one among many factors affecting toxicity.

Inhalation: When the toxin is a gas, it is usually absorbed into the body by inhalation. Inhalation of toxins may cause respiratory and lung damage. Eg: cigarette smoke

Absorption: If a toxin enters the human eye or skin, it can be absorbed into the bloodstream. This is called absorption. The skin can prevent some toxins from entering the body. For example: work stations (gas stations) where people work with toxins

Ingestion means that the person has ingested the toxin. Some chemicals cannot get into blood from digestive tract. For example: drinking contaminated water.

The injected toxin enters the body when the person carrying the toxin breaks the skin. Injections can end in veins, muscles or just under the skin. Eg: Botulinum (used to get rid of wrinkles)

In bio-chemistry, poison, a natural or synthetic substance that damages living tissue and has a harmful or lethal effect on the body, regardless of whether it is absorbed, inhaled or injected through the skin.

7 0

3 years ago

The mass of the products of a chemical reaction will be

In-s [12.5K]

The mass of the product in a chemical reaction must be equal the mass of the reactants.

3 0

3 years ago

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Given the chemical equation, 2Mg + O2 —> 2MgO, when 2.2 g Mg react with 3.6 g of O2, 2.7 g MgO were obtained. What is the per

goldfiish [28.3K]

Always convert to moles when comparing compounds.
Molar mass of a compound is the sum of it's atomic molar mass units.

Mg = 24.3 g/mol Mg
O2 = 16 + 16 = 32 g/mol O2
MgO = 24.3 + 16 = 40.3 g/mol MgO

Determine the moles of each reactant/product.
2.2 g Mg * (1 mol/24.3 g Mg) = 0.09 mol Mg
3.6 O2 * (1 mol/32 g O2) = 0.1125 mol O2
2.7 g MgO * (1 mol/40.3 g MgO) = 0.067 mol MgO

Check if there's a limiting reagent. For every 1 O2 we need 2 Mg
0.1125 mol O2 * 2 = 0.225 mol Mg needed.
So Mg is a limiting reagent. We have plenty of O2 which is typically the case when oxygen is a reactant.

Figure out how much product should form based on the moles of limiting reagent. For every 2 Mg 2 MgO are formed. So it's a 1:1 ratio.
0.09 mol Mg ---> 0.09 mol MgO

compare the expected 0.09 mol MgO to the actual 0.067 mol MgO obtained. Calculate the percent obtained.
(0.067 mol MgO obtained) / (0.09 mol MgO expected) * 100 = 74.44 % yield

8 0

3 years ago