If you sketch the man and the building on paper, you'll have a
right triangle. The right angle is the point where the wall of
the building meets the ground. The height of the building
is one leg of the triangle, the line on the ground from the
building to the man's feet is the other leg, and the line
from his feet to the top of the building is the hypotenuse.
We need to find the angle at his feet, between the hypotenuse
and the leg of the triangle.
Well, the side opposite the angle is the height of the building -- 350ft,
and the side adjacent to the angle is the distance from him to the
building -- 1,000 ft.
The tangent of the angle is (opposite) / (adjacent)
= (350 ft) / (1,000 ft) = 0.350 .
To find the angle, use a book, a slide rule, a Curta, or a calculator
to find the angle whose tangent is 0.350 .
tan⁻¹(0.350) = 19.29° . (rounded)
Compose the quadratic condition in standard shape, ax2 + bx + c = 0. Recognize the values of a, b, c. Write the Quadratic Equation. At that point substitute within the values of a, b, c. Simplify. Check the arrangements.
Answer:
The value of the function f(x) at each point is f(-1) = 5, f(0) = 3, f(1) = 5, f(2) = 11, f(3) = 21 ⇒ A
Step-by-step explanation:
Let us use the mapping shown to solve the question
∵ f(x) = y
∵ x is the domain
∵ y is the range
→ From the figure use x from the domain and y from the range, where
each arrow pointed at the corresponding value y of x
∵ x = -1 and the corresponding value of y is 5
∴ f(-1) = 5
∵ x = 0 and the corresponding value of y is 3
∴ f(0) = 3
∵ x = 1 and the corresponding value of y is 5
∴ f(1) = 5
∵ x = 2 and the corresponding value of y is 11
∴ f(2) = 11
∵ x = 3 and the corresponding value of y is 21
∴ f(3) = 21
The value of the function f(x) at each point is f(-1) = 5, f(0) = 3, f(1) = 5, f(2) = 11, f(3) = 21
