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Sunny_sXe [5.5K]
3 years ago
5

I have no access at 6 pm

Mathematics
1 answer:
notka56 [123]3 years ago
4 0

Answer:

A and E

Step-by-step explanation:

I would plug in N as any number just to see if they are equal. I did 5.

<u>A</u>. 28(5)-35= -105

<u>B</u>. 28(5-35)= -840

<u>C. </u>28(5-7)= -56

<u>D. </u> 7(4*5-35)= -105

<u>E. </u>7(4*5-5)=  105

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the answer is 24

Step-by-step explanation:

68-38 = 24

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Given that log 2 = 0.3010 and log 3 = 0.4771 , how can we find log 6 ? ​
bearhunter [10]

Answer:

\sf \log_{10}6=0.7781

Step-by-step explanation:

<u>Given</u>:

\sf \log_{10} 2 = 0.3010

\sf \log_{10} 3 = 0.4771

To find log₁₀ 6, first rewrite 6 as 3 · 2:

\sf \implies \log_{10}6=\log_{10}(3 \cdot 2)

\textsf{Apply the log product law}: \quad \log_axy=\log_ax + \log_ay

\implies \sf \log_{10}(3 \cdot 2)=\log_{10}3+\log_{10}2

Substituting the given values for log₁₀ 3 and log₁₀ 2:

\begin{aligned} \sf \implies \log_{10}3+\log_{10}2 & = \sf 0.4771+0.3010\\ & = \sf 0.7781 \end{aligned}

Therefore:

\sf \log_{10}6=0.7781

Learn more about logarithm laws here:

brainly.com/question/27953288

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1 year ago
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In a random sample of 535 people 65% said they like cookies with chocolate chips 37% like cookies with peanut butter chips. 25%
Leokris [45]
<h3>The probability that a randomly selected person likes cookies with chocolate or peanut butter chips is 0.77.</h3>

Step-by-step explanation:

Here, the total sample of people has total  535 people.

The percentage of people liking chocolate chip cookies  =  65%

Now, 65% of 535   = \frac{65}{100} \times 535 = 347.75 \approx 348

⇒ 348 people in total like chocolate chip cookies.

⇒ n(C)  = 348

The percentage of people liking peanut butter chip cookies  =  37%

Now, 37% of 535   = \frac{37}{100} \times 535 = 197.95 \approx 198

⇒ 198 people in total like peanut butter chip cookies.

⇒ n(B)  = 198

Percentage of people liking both chocolate &peanut butter chips = 25%  

Now, 25% of 535   = \frac{25}{100} \times 535 =133.75 \approx 134

⇒ 134 people in total like both chocolate &peanut butter chips

⇒ n(C ∩ B )  = 134

Now, n( C U B)  = N(C) + n(B) - n(C ∩ B )

                           = 348 + 198 - 134  = 412

P( person likes cookies with chocolate or peanut butter chips)  

= \frac{\textrm{person likes cookies with chocolate or peanut butter chips}}{\textrm{Total People}}  = \frac{412}{535}  = 0.77

Hence, the probability that a randomly selected person likes cookies with chocolate or peanut butter chips is 0.77.

6 0
3 years ago
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