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Crank
3 years ago
13

How many molecules are in 0.400 moles of. N2O5?

Chemistry
2 answers:
mariarad [96]3 years ago
5 0

Answer:

               2.40 × 10²³ Molecules of N₂O₅

Explanation:

As we know 1 mole of any substance contains 6.022 × 10²³ particles (also called as Avogadro's Number). Therefore, the relation between moles and number of particles can be written as,

             Moles  =  Number of Particles ÷ 6.022 ×10²³ Particles.mol⁻¹

For the molecules of Dinitrogen pentoxide (N₂O₅) it can be written as,

             Moles  =  Number of Molecules ÷ 6.022 ×10²³ Molecules.mol⁻¹

Rearranging for Number of Molecules,

             Number of Molecules  =  Moles × 6.022 ×10²³ Molecules.mol⁻¹

Putting value of Moles,

             Number of Molecules  =  0.400 mol × 6.022 ×10²³ Molecules.mol⁻¹

             Number of Molecules  =  2.40 × 10²³ Molecules of N₂O₅

SpyIntel [72]3 years ago
4 0
Because you're turning moles into molecules, all you need to use is Avogadro's Number (6.022*10^23).
The equation would be: .400 mol N2O5/1 mol*6.022*10^23 molecules. 
The answer, including significant figures, is 151 molecules. 
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A molecule is polar when:
natima [27]
The answer would be B. One region of the molecule has a small negative charge while another region has a small positive charge. However usually in polar bonds, charges or bond between the atoms are unequal (as opposed to having small equal charges).
6 0
3 years ago
The theoretical yield for a reaction is 55.9 g LiCl. The actual yield is 24.6 g LiCl. What is the percent yield of the reaction?
xenn [34]
In chemical reactions, the actual yield is not the same as the expected yield . Actual yield is lower than the theoretical yield . Then we have to find the yield percentage. To see what percentage of the theoretical yield is the actual yield.
Percent yield = actual yield / theoretical yield x 100%
Percent yield = 24.6/55.9 x100%
Percent yield = 44%
7 0
3 years ago
Read 2 more answers
​29. A gas has a volume of 1.75 L at -23°C and 150.0 kPa.
arsen [322]

The answer for the following mention bellow.

  • <u><em>Therefore the final temperature of the gas is 260 k</em></u>

Explanation:

Given:

Initial pressure (P_{1}) = 150.0 kPa

Final pressure (P_{2}) = 210.0 kPa

Initial volume (V_{1}) = 1.75 L

Final volume (V_{2}) = 1.30 L

Initial temperature (T_{1}) = -23°C = 250 k

To find:

Final temperature (T_{2})

We know;

According to the ideal gas equation;

P × V = n × R ×T

where;

P represents the pressure of the gas

V represents the volume of the gas

n represents the no of moles of the gas

R represents the universal gas  constant

T represents the temperature of the gas

We know;

\frac{P*V}{T} = constant

\frac{P_{1} }{P_{2} } × \frac{V_{1} }{V_{2} } = \frac{T_{1} }{T_{2} }

Where;

(P_{1}) represents the initial pressure of the gas

(P_{2}) represents the final pressure of the gas

(V_{1}) represents the initial volume of the gas

(V_{2}) represents the final volume of the gas

(T_{1}) represents the initial temperature of the gas

(T_{2}) represents the final temperature of the gas

So;

\frac{150 * 1.75}{210 * 1.30} = \frac{260}{T_{2} }

(T_{2}) =260 k

<u><em>Therefore the final temperature of the gas is 260 k</em></u>

<u><em></em></u>

3 0
3 years ago
What happens in the process of beta decay?
Andrej [43]

Answer:

A neutron transforms into a proton and an electron.

Explanation:

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6 0
3 years ago
Glucose, C6H12O6,C6H12O6, is used as an energy source by the human body. The overall reaction in the body is described by the eq
Ilia_Sergeevich [38]

Answer:

Mass of oxygen = 61.824 g

Mass of carbon dioxide = 85.01 g

Explanation:

Given data:

Mass of glucose = 58 g

Mass of carbon dioxide = ?

Mass of oxygen = ?

Solution:

First of all we will write the balanced chemical equation,

C₆H₁₂O₆  + 6O₂       →    6CO₂  + 6H₂O

Moles of glucose:

Number of moles = mass / molar mass

Number of moles = 58 g/180 g/mol

Number of moles =  0.322 mol

Now we compare the moles of oxygen with glucose from balance chemical equation.

                             C₆H₁₂O₆          :              O₂  

                                    1                :              6

                                    0.322       :              0.322×6 = 1.932 mol

Mass of oxygen:

Mass of oxygen = number of moles × molar mass

Mass of oxygen =  1.932 mol × 32 g/mol

Mass of oxygen =  61.824 g

Now we compare the moles of carbon dioxide with moles of glucose and oxygen.

                              C₆H₁₂O₆            :              CO₂

                                   1                   :                 6

                                  0.322           :           0.322×6 = 1.932 mol

                                   

                                 O₂                    :                 CO₂

                                  6                     :                  6

                                 1.932                :                  1.932

Mass of carbon dioxide;

mass of carbon dioxide = number of moles × molar mass

mass of carbon dioxide =  1.932 mol × 44 g/mol

mass of carbon dioxide =  85.01 g

7 0
3 years ago
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