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Crank
3 years ago
13

How many molecules are in 0.400 moles of. N2O5?

Chemistry
2 answers:
mariarad [96]3 years ago
5 0

Answer:

               2.40 × 10²³ Molecules of N₂O₅

Explanation:

As we know 1 mole of any substance contains 6.022 × 10²³ particles (also called as Avogadro's Number). Therefore, the relation between moles and number of particles can be written as,

             Moles  =  Number of Particles ÷ 6.022 ×10²³ Particles.mol⁻¹

For the molecules of Dinitrogen pentoxide (N₂O₅) it can be written as,

             Moles  =  Number of Molecules ÷ 6.022 ×10²³ Molecules.mol⁻¹

Rearranging for Number of Molecules,

             Number of Molecules  =  Moles × 6.022 ×10²³ Molecules.mol⁻¹

Putting value of Moles,

             Number of Molecules  =  0.400 mol × 6.022 ×10²³ Molecules.mol⁻¹

             Number of Molecules  =  2.40 × 10²³ Molecules of N₂O₅

SpyIntel [72]3 years ago
4 0
Because you're turning moles into molecules, all you need to use is Avogadro's Number (6.022*10^23).
The equation would be: .400 mol N2O5/1 mol*6.022*10^23 molecules. 
The answer, including significant figures, is 151 molecules. 
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Answer:

The given reaction is a combustion reaction of benzene,

C

6

H

6

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2

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+

15

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2

→

12

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+

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the mass of carbon dioxide

(

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produced from 20 grams (g) of

C

6

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6

is determined through the molar mass of the two compounds, given by,

M

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/

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o

l

M

M

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and their mole ratio:

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m

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2

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C

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H

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→

6

m

o

l

C

O

2

1

m

o

l

C

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H

6

With this,

m

a

s

s

o

f

C

O

2

=

(

20

g

C

6

H

6

)

(

1

m

o

l

C

6

H

6

78.11

g

C

6

H

6

)

(

6

m

o

l

C

O

2

1

m

o

l

C

6

H

6

)

(

44.01

g

C

O

2

1

m

o

l

C

O

2

)

=

(

20

)

(

6

)

(

44.01

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g

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78.11

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g

C

O

2

78.11

m

a

s

s

o

f

C

O

2

=

67.6

g

C

O

2

Therefore, the mass in grams of

C

O

2

formed from 20 grams of

C

6

H

6

is

67.6

g

C

O

2

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it is a problem of app

3 0
2 years ago
Trust me when I say this.
eimsori [14]

Answer:

thank you

So much this was very nice.

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