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2 years ago

Can someone please help me with this ASAP, this is due today, please please help me with this.

Chemistry

1 answer:

hichkok12 [17]2 years ago

5 0

Answer:

this is fairly simple if you have a periodic table with you.

Explanation:

atomic number 17 is Cl mass numer is 35.45 for protons neutron and electron you can just look that up on google. atomic number is where it is at on the periodic table and the mass number is in the little square at the bottom.

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Which combination of factors is most suitable for increasing the electrical conductivity of metals

Lemur [1.5K]

More valence electrons and larger atomic radius are facts most suitable for increasing the electrical conductivity of metals.

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3 years ago

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When the following equation is balanced, what is the coefficient for CaCl2 ?

USPshnik [31]

To know if an equation is balanced you need to check and see how much of each molecule is on either side of the arrow. Right now you have 1-Ca, 2-H, 2-Cl on the left side of the arrow and 1-Ca, 2-Cl, and 2-H on the right side too. Because all the molecules are equal on both sides this means that the equation is balanced. So in front of the CaCl2 there is an assumed coefficient of 1. The answer is 1.

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2 years ago

chemist adds of a M iron(III) bromide solution to a reaction flask. Calculate the mass in grams of iron(III) bromide the chemist

Sav [38]

The question is incomplete, here is the complete question:

A chemist adds 370.0 mL of a 2.25 M iron(III) bromide solution to a reaction flask. Calculate the mass in grams of iron(III) bromide the chemist has added to the flask. Round your answer to 3 significant digits

Answer: The mass of iron (III) bromide is 246. grams

Explanation:

To calculate the mass of solute, we use the equation used to calculate the molarity of solution:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$

We are given:

Molarity of solution = 2.25 M

Molar mass of iron (III) bromide = 295.6 g/mol

Volume of solution = 370.0 mL

Putting values in above equation, we get:

$2.25M=\frac{\text{Mass of solute}\times 1000}{295.6\times 370.0}\\\\\text{Mass of solute}=\frac{2.25\times 295.6\times 370.0}{1000}=246.1g$

Hence, the mass of iron (III) bromide is 246. grams

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2 years ago

In the Alkali metals what element is the same "Period" as the element Neon pls answer

11Alexandr11 [23.1K]

Answer:

Lithium

Explanation:

The answer is lithium because the Alkali metals family is in the group 1A and the element Neon is in the 2 period and they connect at the element Lithium.

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3 years ago

I need help who can help me with this is for an exam

Arturiano [62]

Answer:

Explanation:

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2 years ago