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dalvyx [7]
3 years ago
6

Can someone please help me with this ASAP, this is due today, please please help me with this.

Chemistry
1 answer:
hichkok12 [17]3 years ago
5 0

Answer:

this is fairly simple if you have a periodic table with you.

Explanation:

atomic number 17 is Cl mass numer is 35.45 for protons neutron and electron you can just look that up on google. atomic number is where it is at on the periodic table and the mass number is in the little square at the bottom.

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It is advised that the bromobenzene solution be added slowly to the magnesium-ether solution so that it isn't present in a high
lara [203]

Answer:

Biphenyl

Explanation:

The reaction of bromo benzene with magnesium-ether solution yields a Grignard reagent.

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Hence, It is advised that the bromobenzene solution be added slowly to the magnesium-ether solution so that it isn't present in a high concentration, thus reducing the amount of biphenyl by-product formed.

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3 years ago
Look at sample problem 19.10 in the 8th ed Silberberg book. Write the Ksp expression. Find the concentrations of the ions you ne
777dan777 [17]

Answer:

Explanation:

From the information given:

CaF_2 \to Ca^{2+} + 2F^-

Ksp = 3.2 \times 10^{-11}

no of moles of Ca^{2+} = 0.01 L × 0.0010 mol/L

no of moles of Ca^{2+} = 1 \times 10^{-5} \ mol

no of moles of F^- = 0.01 L × 0.00010 mol/L

no of moles of F^- = 1 \times 10^{-6}\ mol

Total volume = 0.02 L

[Ca^{2+}}] = \dfrac{1\times10^{-5} \ mol}{0.02 \ L} \\ \\  \\  \[[Ca^{2+}}] = 0.0005 \ mol/L

[F^{-}] = \dfrac{(1\times 10^{-6} \ mol)}{0.02 \ L}

[F^{-}] = 5 \times 10^{-5}  \ mol/L

Q = [Ca^{2+}][F^-]^2 \\ \\ Q = 0.0005 \times (5\times 10^{-5})^2 \\ \\ Q = 1.25 \times 10^{-12}

Since Q<ksp, then there will no be any precipitation of CaF2

3 0
3 years ago
URGENT!! 7.(06.02 MC)
dolphi86 [110]

Answer:

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I hope this helps you:)

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