What's your question? is it seprete questions
Answer:
![\lambda= 506.25 nm](https://tex.z-dn.net/?f=%5Clambda%3D%20506.25%20nm)
Explanation:
Diffraction is observed when a wave is distorted by an obstacle whose dimensions are comparable to the wavelength. The simplest case corresponds to the Fraunhofer diffraction, in which the obstacle is a long, narrow slit, so we can ignore the effects of extremes.
This is a simple case, in which we can use the Fraunhofer single slit diffraction equation:
![y=\frac{m \lambda D}{a}](https://tex.z-dn.net/?f=y%3D%5Cfrac%7Bm%20%5Clambda%20D%7D%7Ba%7D)
Where:
![y=Displacement\hspace{3}from\hspace{3} the\hspace{3} centerline \hspace{3}for \hspace{3}minimum\hspace{3} intensity =1.35mm\\\lambda=Light\hspace{3} wavelength \\D=Distance\hspace{3}between\hspace{3}the\hspace{3}screen\hspace{3}and\hspace{3}the\hspace{3}slit=2m\\a=width\hspace{3}of\hspace{3}the\hspace{3}slit=0.750mm\\m=Order\hspace{3}number=1](https://tex.z-dn.net/?f=y%3DDisplacement%5Chspace%7B3%7Dfrom%5Chspace%7B3%7D%20the%5Chspace%7B3%7D%20centerline%20%5Chspace%7B3%7Dfor%20%5Chspace%7B3%7Dminimum%5Chspace%7B3%7D%20intensity%20%3D1.35mm%5C%5C%5Clambda%3DLight%5Chspace%7B3%7D%20wavelength%20%5C%5CD%3DDistance%5Chspace%7B3%7Dbetween%5Chspace%7B3%7Dthe%5Chspace%7B3%7Dscreen%5Chspace%7B3%7Dand%5Chspace%7B3%7Dthe%5Chspace%7B3%7Dslit%3D2m%5C%5Ca%3Dwidth%5Chspace%7B3%7Dof%5Chspace%7B3%7Dthe%5Chspace%7B3%7Dslit%3D0.750mm%5C%5Cm%3DOrder%5Chspace%7B3%7Dnumber%3D1)
Solving for λ:
![\lambda=\frac{y*a}{mD}](https://tex.z-dn.net/?f=%5Clambda%3D%5Cfrac%7By%2Aa%7D%7BmD%7D)
Replacing the data provided by the problem:
![\lambda=\frac{(1.35\times 10^{-3})*(0.750\times 10^{-3})}{1*2} =5.0625\times 10^{-7}m =506.25nm](https://tex.z-dn.net/?f=%5Clambda%3D%5Cfrac%7B%281.35%5Ctimes%2010%5E%7B-3%7D%29%2A%280.750%5Ctimes%2010%5E%7B-3%7D%29%7D%7B1%2A2%7D%20%3D5.0625%5Ctimes%2010%5E%7B-7%7Dm%20%3D506.25nm)
Answer:
500000000 lbft/s
Explanation:
F = Force or weight = 1000000 lbf
s = Displacement = 10000 ft
t = Time taken = 20 seconds
Work done is given by
![W=Fs\\\Rightarrow W=1000000\times 10000\\\Rightarrow W=10000000000\ lb-ft](https://tex.z-dn.net/?f=W%3DFs%5C%5C%5CRightarrow%20W%3D1000000%5Ctimes%2010000%5C%5C%5CRightarrow%20W%3D10000000000%5C%20lb-ft)
Power is given by
![P=\dfrac{W}{t}\\\Rightarrow P=\dfrac{10000000000}{20}\\\Rightarrow P=500000000\ lbft/s](https://tex.z-dn.net/?f=P%3D%5Cdfrac%7BW%7D%7Bt%7D%5C%5C%5CRightarrow%20P%3D%5Cdfrac%7B10000000000%7D%7B20%7D%5C%5C%5CRightarrow%20P%3D500000000%5C%20lbft%2Fs)
One Saucer power is 500000000 lbft/s
If the spaceship's Physicist happens to be hanging out of one side
of the ship, and he measures the speed of the photons as they pass
him and leave the ship, he'll see them passing him at 'c' ... the speed
of light.
When those photons pass somebody who happens to be in their
path, and he decides to measure their speed, he'll see them move
past him at 'c' ... the speed of light.
It doesn't matter whether the observer who measures them is
moving, or at what speed.
And it doesn't matter what source the photons come from, or
whether the source is moving, or at what speed.
And it doesn't matter what the photons' wavelength/frequency is ...
anything from radio to gamma rays.
The photons pass everybody at 'c' ... the speed of light.
Yes, I hear you. That can't be true. It's crazy.
Maybe it's crazy, but it's true.