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Natalija [7]
3 years ago
15

If I turn on a light in a spaceship traveling 1C BACKWARDS, what happens to the photons? Speed -0-, or 1C in opposite direction?

Physics
1 answer:
Advocard [28]3 years ago
5 0

If the spaceship's Physicist happens to be hanging out of one side
of the ship, and he measures the speed of the photons as they pass
him and leave the ship, he'll see them passing him at 'c' ... the speed
of light.

When those photons pass somebody who happens to be in their
path, and he decides to measure their speed, he'll see them move
past him at 'c' ... the speed of light.
 
It doesn't matter whether the observer who measures them is
moving, or at what speed.

And it doesn't matter what source the photons come from, or
whether the source is moving, or at what speed.

And it doesn't matter what the photons' wavelength/frequency is ...
anything from radio to gamma rays.

The photons pass everybody at 'c' ... the speed of light.

Yes, I hear you.  That can't be true. It's crazy.
Maybe it's crazy, but it's true.

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Which statements accurately describe the Doppler effect? Select three options.
Katena32 [7]

Answer:The answer is A,B and C

Explanation: it can be use to learn universe behavior,it is also use for the measurements of velocity of galaxy,and is can also be use to indicate,galaxy motion.

Doppler effect,measures the speed which star and galaxy are moving away from us or towards us. It shows the color of wavelength to be either red shift or blue shift.

6 0
3 years ago
Read 2 more answers
The Grand Canyon is 1800 meters deep at its deepest point. A rock is dropped from the rim above this point. Write the height of
snow_tiger [21]

Answer:

Explanation:

Given

height of grand canyon is h=1800\ m

Rock is dropped i.e. initial velocity is zero

u=0

Using Equation of motion

h=ut+\frac{1}{2}at^2

h=height

u=initial velocity

a=acceleration

t=time

here a=acceleration due to gravity

1800=0+\frac{1}{2}\times 9.8\times t^2

t^2=\frac{2\times 1800}{9.8}

t=19.166\ s

3 0
3 years ago
A gun is fired on a day when the speed of sound is 335 m/s and an echo is heard 0.75 seconds later. How far away is the object t
cricket20 [7]

Answer:

v= 335 m/s

2∆t= 0.75 s

∆x= v.∆t → ∆x= 335×½×0.75 = 125.625 m

8 0
2 years ago
I need to know the right answer to that question
ad-work [718]
The answer is C 8.87*10^4 m/s (it shouldn't be m/s^2 though as velocity is in m/s)

Since you know the acceleration is 12 m/s^2, the initial velocity is 2.39*10^4 m/s and the time (you have to convert to seconds) is 5400 seconds, then you can use the equation

v = vo + at

When you plug in the values you get

v = 2.39*10^4 + 5400*12 . so v = 8.87*10^4 m/s. C is your answer.
8 0
3 years ago
A karate master wants to break a board by hitting the board swiftly with his hand. The master's hand has a mass of 0.30 kg, and
slava [35]

Answer:

f=-1380N

Explanation:

A karate master wants to break a board by hitting the board swiftly with his hand. The master's hand has a mass of 0.30 kg, and as it strikes the board, his hand has a velocity of 23.3 m/s. The master contacts the board for 0.0050 seconds

.the concluding part to the question should be

What is the impact force (impulse) on the board?

solution

from the Newton's second law of motion which states that

the rate of change in momentum is directly proportional to the force applied

f=m(v-u)/t

f=0.3(0-23.3)/0.005

f=-1380N

f=force impact

m=mass of the karates master's hand

t=time for the impact

v=0m/s final velocity

u=initial velocity

6 0
3 years ago
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