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3 years ago

How would you find the density of a gallon of milk?

Physics

2 answers:

AURORKA [14]3 years ago

7 0

Density is the mass divided by the volume

deff fn [24]3 years ago

6 0

Density can be worked out from the weight of a product. Density is mass divided by volume.

To do this you will need a container of which the weight is known, an accurate scale and 1 liter of milk (measured accurately). Weigh the milk and the container, subtract the weight of the container. The density should be roughly 1030 - 1036g/L.

Another option is to get a densitymeter with a scale of 1.000 to 1.100g/L. Put the densitymeter in the milk and read the density off the scale.

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State: the units for acceleration are?

krok68 [10]

A unit of acceleration needs a unit of length in the numerator
and a squared unit of time in the denominator.

Example: meters / second²
      feet / minute²
      smoots / hour²
    furlongs / fortnight² .

Ideally, in order to completely describe an acceleration vector,
you also need to state a direction.

7 0

3 years ago

Un niño amarra una soga a una piedra, y la hace girar como en la gráfica. la piedra realiza un M.C.U, girando con una rapidez de

inessss [21]

Answer:

$\Delta \theta = 56\,rad$

$\Delta \theta \approx 3208.564^{\circ}$

Explanation:

El ángulo barrido en el intervalo de tiempo dado es (The covered angle in the given time interval is):

$\Delta \theta = \omega \cdot \Delta t$

$\Delta \theta = \left(14\,\frac{rad}{s} \rjght)\cdot (4\,s)$

$\Delta \theta = 56\,rad$

$\Delta \theta \approx 3208.564^{\circ}$

4 0

3 years ago

Consider two points in an electric field. The potential at point 1, V1, is 33 V. The potential at point 2, V2, is 175 V. An elec

Mnenie [13.5K]

Answer:

ΔU = e(V₂ - V₁) and its value ΔU = -2.275 × 10⁻²¹ J

Explanation:

Since the electric potential at point 1 is V₁ = 33 V and the electric potential at point 2 is V₂ = 175 V, when the electron is accelerated from point 1 to point 2, there is a change in electric potential ΔV which is given by ΔV = V₂ - V₁.

Substituting the values of the variables into the equation, we have

ΔV = V₂ - V₁.

ΔV = 175 V - 33 V.

ΔV = 142 V

The change in electric potential energy ΔU = eΔV = e(V₂ - V₁) where e = electron charge = -1.602 × 10⁻¹⁹ C and ΔV = electric potential change from point 1 to point 2 = 142 V.

So, substituting the values of the variables into the equation, we have

ΔU = eΔV

ΔU = -1.602 × 10⁻¹⁹ C × 142 V

ΔU = -227.484 × 10⁻¹⁹ J

ΔU = -2.27484 × 10⁻²¹ J

ΔU ≅ -2.275 × 10⁻²¹ J

So, the required equation for the electric potential energy change is

ΔU = e(V₂ - V₁) and its value ΔU = -2.275 × 10⁻²¹ J

5 0

3 years ago

:3333333333333333333333

elixir [45]

Answer:

Cannot see all the answer choices but, when pressure goes up, volume goes down. So your best bet is to choose the graph that has a downward slant.

Explanation:

3 0

3 years ago

An Olympic swimmer swims 50.0 meters in 23.1 seconds . What is his average speed

Aneli [31]

If you take 50 meters and divide by 23.1 seconds, you will get 2.16 meters per second.

So his average speed is 2.16 m/s.

3 0

3 years ago