How to find limiting reagent and theoretical yield khan academy?
1 answer:
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Let the starting position be A, and the ending position of the glide be B.
The triangle ABC shown in the figure, is a right triangle with side lengths 16m and 0.8 m.
The angle of the squirrel's path below the horizon is BAC.
Using right triangle trigonometry:
tan(ABC)=(opposite side)/(adjacent side)=0.8/16=0.05
to find m(ABC) we calculate arctan(0.05) which is 2.86°
Answer: 2.86°
The triangle ABC shown in the figure, is a right triangle with side lengths 16m and 0.8 m.
The angle of the squirrel's path below the horizon is BAC.
Using right triangle trigonometry:
tan(ABC)=(opposite side)/(adjacent side)=0.8/16=0.05
to find m(ABC) we calculate arctan(0.05) which is 2.86°
Answer: 2.86°
Answer:
1)The ball hits the ground after 3 seconds.
2)The maximum height of the ball is 49 feet
3)It takes 1.25 seconds to reach its maximum height
Step-by-step explanation:
Height of building = 40 feet
We are given that A ball is thrown straight up from the top of building with an initial speed of 24 feet per second.
So, The height of the ball as a function of time can be modeled by:
1)After how many seconds the ball hit the ground.
Substitute h(t)=0
So,
Since time cannot be negative
So,the ball hits the ground after 3 seconds.
2)What is the maximum height of the ball?
It takes maximum height at vertex
Formula :
Substitute the value of t in function
So,the maximum height of the ball is 49 feet
3).How long did it take for the ball to reach its maximum height?
It takes 1.25 seconds to reach its maximum height