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3 years ago

Which type of weathering creates karst topography

Physics

2 answers:

vekshin13 years ago

8 0

Karst topography is created by the chemical weathering process of carbonation

Kitty [74]3 years ago

5 0

Karst topography is created by the chemical weathering process of CARBONATION. Carbonation affects limestone and other carbonate rocks. The action of carbonation creates a distinctive landscape of little surface drainage, sink holes, caves and cockpits.

Rain water mixes with carbon dioxide in the atmosphere to form a weak carbonic acid. The carbonic acid then reacts with the calcium carbonate in the rocks to form a soluble calcium bicarbonate that is easily washed away by water.

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If you mix 100 g of ice at 0 ∘c with 100 g of boiling water at 100 ∘c in a perfectly insulated container, the final stabilized t

loris [4]

The final stabilized temperature will be between 0 °C and 50 °C.

<h3>Calorimetry:</h3>

The enthalpy of fusion of ice is 334 J/g. The specific heat of water is 4.2 J/g.

To cool 100 g of water from 100 °C to 0 °C would require the removal of

4.2 x 100 x 100 = 42000 J.

To melt the ice would require the addition of

334 x 100 = 33400 J

∴ 42000 > 33400 thus you can melt all the ice and have some heat to spare, specifically 42000 - 33400 = 8600 J

Now use this to warm up 100+100 = 200 g of water at 0 °C

The final stabilized temperature;

8600 / (200 x 4.2) = 10.23 °C

Therefore, the final stabilized temperature is 10.23 °C

Learn more about Calorimetry here:

brainly.com/question/1989313

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4 0

2 years ago

A block of mass 5.6 kg is attached to a horizontal spring on a rough floor. Initially the spring is compressed 3.5 cm. The sprin

Mariana [72]

Answer:

The velocity of block = 0.188 $\frac{m}{s}$

Explanation:

Mass m = 5.6 kg

k = 1040 $\frac{N}{m}$

$\mu$ = 0.26

$x_{1} =$ 0.035 m , $v_{1}$ = 0

$x_{2} =$ 0.02 m

From work energy theorem

$K_{1} + U_{1} + W_{other} = K_{2} + U_{2}$ --------- (1)

Kinetic energy

$K = \frac{1}{2} k x^{2}$ ------- (1)

Potential energy

$U = \frac{1}{2} k x^{2}$ ------- (2)

Work done

W = F.s ------ (3)

From Newton's second law

$R_{N}$ = mg

$R_{N}$ = 5.6 × 9.81 = 54.9 N

Friction force = 0.4 × 54.9 = 21.9 N

Now the work done by the friction

$W_{f}$ = - 21.9 × 0.015

$W_{f}$ = - 0.329 J

Now kinetic energy

At point 1

$K_{1} = \frac{1}{2} m v^{2} _{1}$

$K_{1} = 0$

$U_{1} = \frac{1}{2} k x^{2}$

$U_{1} = \frac{1}{2} (1040) 0.035^{2}$

$U_{1} =$ 0.637 J

At point 2

$K_{2} = \frac{1}{2} (5.6) v^{2} _{2}$

$K_{2} = 2.8 v_{2} ^{2}$

Potential energy

$U_{2} = \frac{1}{2} k x_2^{2}$

$U_{2} = \frac{1}{2} (1040) 0.02^{2}$

$U_{2} = 0.208$ J

From equation (1) we get

0 + 0.637 - 0.329 = 2.8 $v_{2} ^{2}$ + 0.208

2.8 $v_{2} ^{2}$ = 0.1

$v_{2} =$ 0.188 $\frac{m}{s}$

This is the velocity of block.

6 0

4 years ago

A man standing on a bus remains still when the bus is at rest. When the bus moves forward and then slows down the man continues

vovikov84 [41]

When the bus starts moving forward, the man remains at rest,
causing him to lean back.

When the bus slows down, the man continues to move forward,
and appears to lean forward.

Both events are examples of the effect of inertia.

6 0

4 years ago

Problem 1: Spherical mirrorConsider a spherical mirror of radius 2 m, and rays which go parallel to the optic axis. What is thep

SIZIF [17.4K]

Answer:

1) iii i= 1m, 2) iii and iv, 3) i = f₂ (L-f₁) / (L - (f₁ + f₂))

Explanation:

Problem 1

For this problem we use two equations the equations of the focal distance in mirrors

f = r / 2

f = 2/2

f = 1 m

The builder's equation

1 / f = 1 / o + 1 / i

Where f is the focal length, "o and i" are the distance to the object and the image respectively.

For a ray to arrive parallel to the surface it must come from infinity, whereby o = ∞ and 1 / o = 0

1 / f = 0 + 1 / i

i = f

i = 1 m

The image is formed at the focal point

The correct answer is iii

Problem 2

For this problem we have two possibilities the lens is convergent or divergent, in both cases the back face (R₂) must be flat

Case 1 Flat lens - convex (convergent)

R₂ = infinity

R₁ > 0

Cas2 Flat-concave (divergent) lens

R₂ = infinity

R₁ <0

Why the correct answers are iii and iv

Problem 3

For a thick lens the rays parallel to the first surface fall in their focal length (f₁), this is the exit point for the second surface whereby the distance to the object is o = L –f₁, let's apply the constructor equation to this second surface

1 / f₂ = 1 / (L-f₁) + 1 / i

1 / i = 1 / f₂ - 1 / (L-f₁)

1 / i = (L-f₁-f₂) / f₂ (L-f₁)

i = f₂ (L-f₁) / (L - (f₁ + f₂))

This is the image of the rays that enter parallel to the first surface

6 0

4 years ago

a bowling ball and a baseball both roll across your foot at the same speed. The bowling ball hurts more

Maru [420]

Answer:

you are right bowling ball has more mass and it is denser than a baseball

Explanation:

5 0

3 years ago

Read 2 more answers