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3 years ago

Which geographic features are associated with a divergent boundary (Can select more then one)

Chemistry

2 answers:

chubhunter [2.5K]3 years ago

6 0

I think it’s hydrothermal vents, rifts and subduction trench

Alla [95]3 years ago

4 0

I'm most likely too late but I'll answer it anyways.

The answers are Hydrothermal vents, and Rifts.

Reasoning: Hydrothermal vents are basically splits in the ocean floor reaching down to the mantle, it being caused by diverging plates makes sense.

Continental mountains are wrong and I don't think I need to explain why.

Ridges are basically a long line of peaks (sort of) it's not something diverging plates would cause.

Subduction trenches are formed from subduction zones from one plate folding under another which can only happen if there is a convergent boundary.

Rifts are basically long splits in the ground, like ridges but inverted, this is the second correct answer.

Hope this helps.

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3 years ago

The activation energy of a certain uncatalyzed biochemical reaction is 50.0 kJ/mol. In the presence of a catalyst at 37°C, the r

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Answer:

E₁ ≅ 28.96 kJ/mol

Explanation:

Given that:

The activation energy of a certain uncatalyzed biochemical reaction is 50.0 kJ/mol,

Let the activation energy for a catalyzed biochemical reaction = E₁

E₁ = ??? (unknown)

Let the activation energy for an uncatalyzed biochemical reaction = E₂

E₂ = 50.0 kJ/mol

= 50,000 J/mol

Temperature (T) = 37°C

= (37+273.15)K

= 310.15K

Rate constant (R) = 8.314 J/mol/k

Also, let the constant rate for the catalyzed biochemical reaction = K₁

let the constant rate for the uncatalyzed biochemical reaction = K₂

If the rate constant for the reaction increases by a factor of 3.50 × 10³ as compared with the uncatalyzed reaction, That implies that:

K₁ = 3.50 × 10³

K₂ = 1

Now, to calculate the activation energy for the catalyzed reaction going by the following above parameter;

we can use the formula for Arrhenius equation;

$K=Ae^{\frac{-E}{RT}}$

If $K_1=Ae^{\frac{-E_1}{RT}} -------equation 1$ &

$K_2=Ae^{\frac{-E_2}{RT}} -------equation 2$

$\frac{K_1}{K_2} = e^{\frac{-E_1-E_2}{RT}$

$E_1= E_2-RT*In(\frac{K_1}{K_2})$

$E_1= 50,000-8.314*310.15*In(\frac{3.50*10^3}{1})$

$E_1 = 28957.39292$ $J/mol$

E₁ ≅ 28.96 kJ/mol

∴ the activation energy for a catalyzed biochemical reaction (E₁) = 28.96 kJ/mol

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