<h3><u>Answer;</u>
</h3>
= 607.568 Torr
<h3><u>Explanation;
</u></h3>
1 in of mercury is equivalent to 25.4 Torr
Therefore;
23.92 InHg will be equal to;
23.92 × 25.4
<u>= 607.568 Torr</u>
We have that the molecular weight (3sf) of the compound (g/mol)

From the question we are told
A solution made by mixing 20.0 g of a non-volatile compound with 125 mL of water at 25°C has a vapor pressure of 22.67 torr. What is the molecular weight (3sf) of the compound (g/mol).
Generally the equation for the Rouault's law is mathematically given as
P=P_0 N

Therefore
The molecular weight (3sf) of the compound (g/mol)
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Answer:
36.8 L
Explanation:
We'll begin by converting 80 °C to Kelvin temperature. This can be obtained as follow:
T(K) = T(°C) + 273
T(°C) = 80 °C
T(K) = 80 + 273
T(K) = 353 K
Finally, we shall determine the volume occupied by the helium gas. This can be obtained as follow:
Number of mole (n) = 1.27 moles
Temperature (T) = 353 K
Pressure (P) = 1 atm
Gas constant (R) = 0.0821 atm.L/Kmol
Volume (V) =?
PV = nRT
1 × V = 1.27 × 0.0821 × 353
V = 36.8 L
Thus, the volume occupied by the helium gas is 36.8 L