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rosijanka [135]
3 years ago
7

Alligators are the large predators that eat many smaller animals in a swamp how might removing the alligators from a swamp habit

at create a decrease vegetation
Chemistry
1 answer:
ANTONII [103]3 years ago
4 0
Removing the alligators will cause the smaller animals to increase in population causing the grasses, plants they eat to began to decrease because they can’t produce fast enough
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The weight percent of concentrated H2SO4, molar mass=980 g/mol, is 960% and its density is 184 g/ml. What is the molarity of con
Elan Coil [88]

Answer:

<em>C</em> H2SO4 = 9.79 M

Explanation:

  • molarity (M) ≡ # dissolved species / V sln
  • H2SO4 ↔ H3O+  +  SO4-

∴ %w/w H2SO4 = 960% = g H2SO4 / g sln * 100

⇒ 9.6 = g H2SO4 / g sln

calculation base: 1000 g sln

⇒ g H2SO4 = 9600g

⇒<em> </em>mol<em> </em>H2SO4 =<em> </em>9600 g H2SO4 * ( mol H2SO4/ 980g H2SO4 ) = 9.796  mol H2SO4

⇒ V sln = 1000g sln / 1000g/L = 1 L sln

∴ ρ H20 ≅ 1000 Kg/m³ = 1000 g/L

⇒ <em>C</em> H2SO4 = 9.796 mol H2SO4 / 1 L sln

⇒ <em>C</em> H2SO4 = 9.796 M

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Consider the reaction where barium sulfate can be prepared from 2.76 mol of sodium sulfate and excess barium acetate. Sodium ace
MAXImum [283]

Answer:

1. Na2SO4(aq)+C4H6BaO4(aq) --> BaSO4(s) + 2C2H3NaO2(aq)

2. 2Na^+1(aq) + SO4^-2(aq) + 4C^+4(aq) + 6H^+1(aq) + Ba^-2(aq) + 4O^-2(aq) --> BaSO4(s) + 2C^-4(aq) + 2H^+1(aq) + 3Na^+1(aq) + 2O^-2(aq)

3. Ba^+2(aq) + SO4^-2(aq) --> BaSO4(s)

Explanation:

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Chromosomal walking is a positional cloning method used to find, isolate, and clone a specific allele in a gene library.

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1) A 10g sample of H2(g) reacts with a 22g sample of O2(g) according to
solmaris [256]

Answer:

H₂ is excess reactant and O₂ the limiting reactant

Explanation:

Based on the chemical reaction:

2H₂(g) + O₂(g) → 2H₂O

<em>2 moles of H₂ react per mole of O₂</em>

<em />

To find limiting reactant we need to convert the mass of each reactant to moles:

<em>Moles H₂ -Molar mass: 2.016g/mol-:</em>

10g H₂ * (1mol / 2.016g) = 4.96 moles

<em>Moles O₂ -Molar mass: 32g/mol-:</em>

22g O₂ * (1mol / 32g) = 0.69 moles

For a complete reaction of 0.69 moles of O₂ are needed:

0.69mol O₂ * (2mol H₂ / 1mol O₂) = 1.38 moles of H₂

As there are 4.96 moles,

<h3>H₂ is excess reactant and O₂ the limiting reactant</h3>
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3 years ago
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